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loveweak-blog1 · 7 years ago
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loveweak-blog1 · 7 years ago
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loveweak-blog1 · 7 years ago
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NCERT Solutions for Class 10 Maths Chapter 10 Circles
This content is part of NCERT Solutions for Class 10 Maths Chapter 10 Circles
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9.4        THEORM :
 Statement :       Lengths of two tangents drawn from an external point to a circle are equal.
Given:              AP and AQ are two tangents drawn from a point A to a circle C (O, r).
 To prove :        AP = AQ
 Construction :  Join OP, OQ and OA.
 Proof :              In AOQ and APO    
                       [Tangent at any point of a circle is perp. to radius through the point of contact]
AO = AO           [Common]
OQ = OP          [Radius]
So, by R.H.S. criterion of congruency
          AQ = AP           [By CPCT]                                 Hence Proved.
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loveweak-blog1 · 7 years ago
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NCERT Solutions for Class 10 Maths Chapter 6 Triangles: THALES THEOREM
This content is part of NCERT Solutions for Class 10 Maths Chapter 6 Triangles
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THALES THEOREM (BASIC PROPROTIONALITY THEOREM) :
 Statement :          If a line is drawn parallel to one side of a triangle to intersect the other sides in distinct points, then the other two sides are divided in the same ratio.
 Given:                   A triangle ABC in which a line parallel to side
BC intersects other two sides AB and AC at D and
E respectively.
To Prove :            
Construction :    Join BE and CD and draw DMAC and ENAB.
Proof :                   Area of DADE (=base × height) = AD × EN.
                               Area of DADE is denoted as are (ADE)
                               So,          ar(ADE) = DB × EN
                               And       ar(BDE) = DB × EN ,
                               Therefore,                  ….(i)
                               Similarly,             ar(ADE =AE × DM and ar(DEC =EC × DM.
                               And                                            ......(ii)
Note that D BDE and D DEC are on the same base DE and between the two parallel lines BC and DE.
                               So,                          ar(BDE) = ar(DEC)                            .....(iii)
                               Therefore, from (i), (ii) and (iii), we have :  
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loveweak-blog1 · 7 years ago
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Natural History Museum 03.08.18
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loveweak-blog1 · 7 years ago
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loveweak-blog1 · 7 years ago
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loveweak-blog1 · 7 years ago
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loveweak-blog1 · 7 years ago
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this is probably the best thing i have ever made
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loveweak-blog1 · 7 years ago
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loveweak-blog1 · 7 years ago
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loveweak-blog1 · 7 years ago
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Northern California ‘Forest House’
© Richard Barnes
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loveweak-blog1 · 7 years ago
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Northern California ‘Forest House’
© Richard Barnes
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loveweak-blog1 · 7 years ago
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loveweak-blog1 · 7 years ago
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Niken Anindita  -  https://nikenanindita.wordpress.com  -   http://www.pixiv.net/member.php?id=2130339  -  http://megatruh.tumblr.com -  http://society6.com/megatruh
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