#also nilpotent on the space of all polynomial functions
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@greetings-inferiors idk how to say this without seeming stupid so ill just say it. i dont know how differentiation works anymore.
#i dont need it so its ok#the differentiation operator is unbounded#also nilpotent on the space of all polynomial functions#also also it has an invariant space generated by e^x#as well as one generated by sin and cos#thats all i need to know#chain rule? product rule? idk them sorry
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