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This Day In SpongeBob History

Have You Seen This Snail, aired November 11, 2005. season 4, episode 63.

The feels. 

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when you’re trying to keep it lowkey in front of your coworkers but fail miserably because of your touchy feely boyfriend

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I love you

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they said going to work every day so u can support ur young unemployed live-in boyfriend is feminism  

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Lockscreens - Legend of Fu Yao

I’m obsessed with this drama ; v ;

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Disney Gentlemen + Different ways to say “I love you”

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Once Upon a Time in Lingjian Mountain | Wrong script

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i think humanity’s love affair with the sea is perhaps the sexiest thing about us 

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casual intimacy kills me every time. grand gestures are cute and all but seeing two people who are just totally comfortable with having each other in their space, who dont think twice about leaning into each other and thoughtlessly holding each other while doing unrelated things….. thats love

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Spongebob Squarepants season 6, episode 002: Not Normal

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Yves Olade, When Rome Falls

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“I am a simple person with simple wants,” I say, scrolling through AO3 and ignoring fics for a variety of petty reasons

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Oh, honey. Goddesses don’t speak in whispers. They scream.

the countess // room service (via ta-ta-tate)

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can you explain the Monty hall problem?? I’m trying to wrap my head around it, but I just don’t understand

OH okay I actually have a really good explanation for this one, thanks to my number theory professor from college

so the Monty Hall problem is the setup of “there are three doors, behind one is a car and behind two are goats. you keep what is behind the door you pick and for the sake of the game you want a car not a goat, live your best goat life irl and not on my math problem. you pick one door. the announcer, who already knows what door the car is behind, reveals one of the doors that you haven’t picked as a goat. you have the opportunity to switch or not. should you?”

the instinctive answer is “eh why the fuck should I, it’s a 50/50 chance?”

but that’s the wrong answer, the mathematical answer is “it’s 2/3rds to get the car if you switch and 1/3rd if you don’t”

there are a lot of ways to mathematically convince yourself of that fact; probably the easiest way bc it’s a problem with a very small number of possibilities is just to chart out literally every single possibility, and then count number of times that a switch wins, and number of times that a stay wins. (ie, if the car is behind door 1, there are three possibilities of you pick door 1, 2, or 3, and then for each of those, either two or one possibilities of what the host picks.) you could plug it into a conditional probability formula. but my favorite intuitive solution is the following:

just re-imagine the problem with 100 doors. you pick one door out of 100 at random, 99 with goats behind them and one with a car behind it. your host opens 98 doors all with goats. you have the choice to keep the door that you picked, or choose the door that the host didn’t open. do you switch?

well, obviously. you had a 1/100 chance of getting it right in the first place, whereas the host knows where the car is, there is a 99% chance it was under one of the doors that you didn’t pick, and, well, now there’s only one option for “one of the doors that you didn’t pick” so there’s a 99% chance it was behind that one.

it’s just the same thing when there are three doors! there was a 33% chance you were right and a 66% chance it was in “one of the doors that you didn’t pick”, and the host opening the other doors “concentrates” that probability on just one door. so there’s still a 2/3rds chance it’s behind that door and 1/3rd it was behind your original, and not a 50/50 anything.

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Leave a light on for me. I love you.