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Can The Motion Be Transported From Jupiter To The Inner Planets?
Data No. (1)
13.1 km/s x 10500s = 137550 km = 4.7 km/s x 14178 s x 2 (error 3%)
And
4.7 km/s x 14178 s =2π x 29.8 km/s x 366.7 s (error 3%)
4.7 km/s x 14178 s = (π+1) x 24.1 km/s x 671 s
Where
13.1 km /s = Jupiter Velocity
4.7 km /s = Pluto Velocity
29.8 km/s = Earth velocity
24.1 km/s = Mars velocity
10500 = The factor (s) of Jupiter motion
(Jupiter rotation period is 9.9 hours and Jupiter orbital period is 4331 days- means- Jupiter orbital period has 10500 rotation periods – means- The factor (s) =10500)
14178 = The factor (s) of Pluto motion
671 = The factor (s) of Mars motion
366.7 = The factor (s) of The Earth motion
Data No. (2)
13.1 km/s x 17.2 x 3600 = 2 x 406000 km
13.1 km/s x 53.9 x 3600 = 2.54 million km
Where
17.2 hours = Uranus rotation period
53.9 hours = Rotation Periods Total of (Jupiter + Saturn + Uranus + Neptune)
53.9 hours = 17.2 h x π
406000 km = The planets diameters total = The Moon Orbital Apogee Radius
2.54 million km = The Earth Moon Orbital Apogee Circumference
Data No. (3)
2.59 million km / 142984 km = 142984 km/7510 km (error 5%)
Where
2.59 million km = Pluto motion distance in its rotation period (the transported motion)
142984 km = Jupiter diameter
7510 km = Pluto Circumference
Data No. (4)
13.1 km/s x 10921 s = 142984 km -And
4900 million km = 449197 km x 10921 km - where
13.1 km /s = Jupiter Velocity
10921 km = The Moon Circumference
142984 km = Jupiter Diameter
449197 km = Jupiter Circumference
4900 million km = Jupiter Orbital Circumference
Data No. (5)
4900 million km = 1.392 mkm x 3475 km = 406000 km x 12104 km = 384000 km x 12756 km = 363000 x 2 x 6792 km = 51118 km x 49528 km x 2 (Max error 3%) where
4900 million km = Jupiter Orbital Circumference
1.392 million km = The Sun Diameter
3475 km = The Moon Diameter
12104 km = Venus Diameter
12756 km = The Earth Diameter
6792 km = Mars Diameter
406000 km = The Moon Orbital Apogee Radius
384000 km = The Moon Orbital Distance
363000 km = The Moon Orbital Perigee Radius
DISCUSSION
Data No. (1)
(No. A)
13.1 km/s x 10500s = 137550 km = 4.7 km/s x 14178 s x 2 (error 3%)
(137550 km = 142984 km "Jupiter diameter" with error 4%)
And
142984 km = 4.7 km/s x 14178 s x 2 x 1.0725
(No. B)
4.7 km/s x 14178 s = 2π x 29.8 km/s x 366.7 s (error 3%)
4.7 km/s x 14178 s = (π+1) x 24.1 km/s x 671 s
(No. C)
9.7 km/s x 24105 s x 2 = 467645 km
5.4 km/s x 89143 s = 481372 km = 449197 km x 1.0725 = 155597 km x π
6.8 km/s x 42683 s = 290240 km = (155597 km x 2) / (1.0725)
(No. D)
155597 km = 1.0725 x (142984 km = Jupiter diameter) (error 1.5%)
Where
13.1 km /s = Jupiter Velocity
4.7 km /s = Pluto Velocity
29.8 km/s = Earth velocity
24.1 km/s = Mars velocity
10500 = The factor (s) of Jupiter motion
14178 = The factor (s) of Pluto motion
671 = The factor (s) of Mars motion
366.7 = The factor (s) of The Earth motion
24105 = The factor (s) of Saturn motion
42683 = The factor (s) of Uranus motion
89143 = The factor (s) of Neptune motion
DISCUSSION
let's remember why we analyze this data ….
(1)
I suppose the motion is transported among the planets –
In details – Pluto (4.7 km/s) moves in its rotation period (153.3 hours) a distance = 2.59 million km- I claim this motion is transported among the planets till reach to the Earth moon –
Means- this motion is transported from Pluto to Neptune then to Uranus then to Saturn then to Jupiter then to the Earth moon- we analyze this data to prove this idea.
(2)
The data we analyze here is a strong proof for the idea- let's explain how this data is created-
I define the factor (s) for each planet – and multiply it with its planet velocity and then compare the results – let's refer to the details in following…
(a)
The factor 's" = the planet rotation periods number in its orbital period- for example- let's define the factor "s" for Jupiter – Jupiter orbital period =4331 days and Jupiter rotation period is 9.9 hours by that Jupiter has 10500 rotation periods in its orbital period- means – the factor "s" for Jupiter = 10500
Means Jupiter has 10500 (Jupiter rotation periods) in its orbital period (4331 solar days) – means- 9.9 hours x 10500 = 4331 days x 24 hours
For that the value (10500) units be (Jupiter rotation period 9.9 hours)
BUT
We will use this value (10500) as a period of time in seconds – means
We use this value as (10500 seconds)
Now let's define the value (SV) where
S= the "s" factor (we have defined now) and
V= the planet velocity
Now - Jupiter (13.1 km/s) moves in (10500 seconds) a distance = 137550 km
Means (sv) for Jupiter = 137550 km
This data can be analyzed in 2 points
(First Point)
Let's find (SV) for Pluto
Pluto (4.7 km/s) moves during (14178 s) a distance = 133273 km /2
(between 137550 km and 133273 km an error 3%)
By that (SV) (For Jupiter) = 2 x (SV) (For Pluto) (error 3%)
This information is very important because it supports the motion transportation idea- shortly- if the motion is transported between Pluto and Jupiter that necessitates to produce equal values for both-
(of course the rate "2" can't refute this idea because the rate"2" tells Pluto needs to move 2 cycles to cause Jupiter to move one cycle)
Shortly
The equal results should be considered as a proof for the transportation of motion
Please Note
(SV) for Pluto = 4.7 km/s x 14178 s = 2π x 29.8 km/s x 366.7 s (error 3%)
Means
(SV) for Pluto = 2π x (SV) for The Earth
Shortly
If (SV) Pluto = 4.7 km/s x 14178 s = (A) then
(SV) Jupiter = (2A)
(SV) Earth = (A/2π)
(SV) Mars = (A/(π+1))
These results prove the motion is transported among these planets- that causes the results to be almost equal (or in full proportionality)
Notice
Mars is a migrant planet for that the rate (π+1) is used as exceptional
(Second Point)
13.1 km/s x 10500 seconds = 137550 km = 142984 km (Jupiter diameter) (error 4%)
Means
(SV) Jupiter produces a distance = Jupiter Diameter (error 4%)
(SV) Pluto produces a distance = Jupiter Radius (error 3%)
(SV) Earth produces a distance = (Jupiter Radius/2π) (error 4%)
(SV) Mars produces a distance = (Jupiter Radius/(π+1)) (No error)
This data tells very important idea – it tells- the (SV) values of the four planets (Pluto, Jupiter, the Earth and Mars) are in full proportionality- that we can consider them equal values- this result is done because the motion is transported among the planets- and this transported motion causes to define Jupiter diameter where the planet diameter equation uses this transported motion to perform the equation geometrical effect.
That proves the transported motion causes the equation effect.
Notice
(SV) Pluto x 2 = Jupiter diameter /(1.0725)
We know the rate (1.0725) is found as a general phenomenon has effect on all planets data (point No.7-4) – that shows the reason behind the great error (3% and 4%) because there's (7.25%) as a difference in values created by the rate (1.0725) effect.
The Discussion Of The Data No. (C)
Data (No. C)
9.7 km/s x 24105 s x 2 = 467645 km
5.4 km/s x 89143 s = 481372 km = 449197 km x 1.0725 = 155597 km x π
6.8 km/s x 42683 s = 290240 km = (155597 km x 2) / (1.0725)
(No. D)
155597 km = 1.0725 x (142984 km = Jupiter diameter) (error 1.5%)
The distance (467645km) is related to Jupiter circumference (449197 km) (error 4%)
And
The distance 481372 km is related to circumference (449197km) by the rate (1.0725)-
Also we see (SV) Uranus (290240 km) is related to Neptune circumference by the rate (1.0725) – where Neptune Circumference 155597 km = 1.0725 x 142984 km (Jupiter Diameter)
This analysis leads us to the next conclusion
The values (SV) of (Saturn, Uranus and Neptune) is related to (Jupiter circumference)
Shortly
The Values (SV) for (Pluto, Jupiter, The Earth and Mars) produces (Jupiter Diameter)
And
The values (SV) of (Saturn, Uranus and Neptune) produces (Jupiter Circumference)
These results are logical and supports the idea – because the idea tells (the motion is transported among the planets) –
In details- Pluto (4.7 km/s) moves in its rotation period (153.3 h) a distance = 2.59 million km and this motion is transported among the planets – means- this motion is transported from Pluto to Neptune then to Uranus then to Saturn then to Jupiter then to the Earth moon (and at end the motion reach to Mars)
The idea is understandable and the data supports it clearly – that because-
If the motion is transported really among the planets- that means- we have one amount of energy is transported through many points and this amount of energy is seen in the data as equal values are produced by all planets.
And
Because the transported motion causes to define each planet diameter – and because the planet diameter equation depends on this transported motion – for that reason- the planets diameter equation data shows this equality of values (the transported energy)
Shortly –
The idea is supported strongly by the planets data
Deep Discussion
We need to remember the matter creation new vision to see the important effect of the analyzed data –
I suppose the solar system is consisted of one stream of energy
By that- the solar system is similar to one sea of water (or one ocean)
The planet (matter) is similar to a whirlpool (vortex) found on the sea page
The whirlpool is the best idea to see the matter creation new vision
Where – the whirlpool dimensions are defined by the water motion features – for example – we have one whirlpool its diameter is 5 meters – this diameter is defined by the water motion features (the velocity, the direction, the water amount, the pressure …etc)
Here we see simply the whirlpool has input and output – because the sea water moves through this whirlpool – by that – we notice the input amount of water is equal the output amount of water – it's very important feature because it tells there's a stability in the system- let's imagine the water output through this whirlpool is less than its input amount – what would happen? This whirlpool will be destroyed and can't continue in the existence because the system has no a stability – on the contrary- the system stores the sea water inside the whirlpool and then the stored water will destroy the whirlpool
I tried to explain the importance of the previous data because it supports greatly the idea and proved it's a fact – where the motion really is transported among the planets.
NOTICE
The previous data should be considered proves for the planet diameter equation concept- also I provide more proves in point no. (9) which prove the equation concept- these proves and the provided data are very important and I put them to prove that (The Equation Data Is Not An Unique Group Of Data) on the contrary the equation concept is supported by huge amount of the planets data by that I prove that the equation is not a tree in a desert –instead- the planets data supports the equation concept with huge amount of proves.
Data No. (2)
13.1 km/s x 17.2 x 3600 = 2 x 406000 km
13.1 km/s x 53.9 x 3600 = 2.54 million km
Where
17.2 hours = Uranus rotation period
53.9 hours = Rotation Periods Total of (Jupiter + Saturn + Uranus + Neptune)
53.9 hours = 17.2 h x π
406000 km = The planets diameters total = The Moon Orbital Apogee Radius
2.54 million km = The Earth Moon Orbital Apogee Circumference
DISCUSSION
I still prove the motion is transported from Pluto to the Moon through all planets- we remember Pluto (4.7 km/s) moves in its rotation period (153.3 hours) a distance = 2.59 million km- and this motion is transported to the Earth moon
Here we study (How Does Jupiter Transport The Motion To The Moon?)
Let's discuss Data No. (2)
Let's summarize the idea in following
Jupiter received a transported motion for a distance =2.59 million km from (Saturn) and Jupiter will transport this motion to the Earth moon.
Jupiter makes some geometrical effects on this distance before to transport it to the moon – let's consider these geometrical effects in following
(a)
At first, Jupiter sees the distance (2.59 million km) as an orbital circumference and defines its radius (2.59 million km = 2π x 413600 km) and also Jupiter (modified) the radius (413600 km) to be (406000 km) (error 2%)
(406000 km =The Planets Diameters Total) by that Jupiter decides (the planets diameters total will be 406000 km) that explains why Jupiter defines the radius and also explains why Jupiter diameter = 8 planets diameters total (because the planets diameters total is created based on Jupiter diameter- this is explained in Jupiter diameter analysis Point no.8-10)
(b)
Jupiter (13.1 km/s) moves the distance 406000 km x 2 in a period of time = 17.2 hours – by that – Jupiter creates the period 17.2 hours
And
Jupiter (13.1 km/s) moves the circumference 2.54 million km in a period of time =53.9 hours – by that –Jupiter creates the period 53.9 h (where 53.9 h= π x 17.2 h)
I want to say
These 2 periods (17.2 h and 53.9 h) are defined based on Jupiter motion and velocity to pass the transported motion (2.59 million km) (error 2%)
This definition of the periods depends on the definition of the orbital circumference (2.54 million km) and its radius 406000 km
This definition creates many important results
(1st Result)
Jupiter defined the period 17.2 hours as (Jupiter rotation period) – I suppose Jupiter rotation period was 17.2 hours and it's changed later (I prove this fact in point no. 8)
(2nd Result)
Jupiter defined the period 53.9 hours to be the four planets rotations periods total (Jupiter rot. per. 9.9h + Saturn rot. per. 10.7 h+ Uranus rot. per. 17.2 h + Neptune rot. per. 16.1 h) = 53.9 hours
Shortly – Jupiter defined each planet rotation period
(3rd Result)
Each planet (Jupiter, Saturn, Uranus and Neptune) will define its own circumference based on the defined rotation period and its own velocity.
Means- Jupiter definition for each planet rotation period caused also to define each planet circumference (and diameter) – because – the four planets follow the rule (the planet moves in its rotation period a distance = Its circumference)
Notice
We accept that, the planet matter is similar to a whirlpool is found on the sea page, and we know (the matter dimensions are defined based on the motion features)- here we have application for this idea – Jupiter motion defines the period 53.9 hours and based on this period each planet rotation period is defined- now – each planet will define its circumference by its motion during its rotation period – means each planet matter is created here after Jupiter definition for the period 53.9 hours
Shortly – the definition of the period 53.9 hours was the motion features by which the matter dimensions are created.
(4th Result)
Jupiter transported the motion to the moon with the geometrical effects are found by Jupiter motion for that the moon orbit is created by these effects of Jupiter motion
Shortly
The moon orbital apogee radius = 406000 km
The moon orbital apogee circumference = 2.54 million km
Data No. (3)
2.59 million km / 142984 km = 142984 km/7510 km (error 5%)
Where
2.59 million km = Pluto motion distance in its rotation period (the transported motion)
142984 km = Jupiter diameter
7510 km = Pluto Circumference
The data shows – Jupiter diameter (142984 km) is created based on the transported motion distance 2.59 million km and Pluto circumference (7510 km) is created based on Jupiter diameter
The data tells how Jupiter diameter and Pluto circumference are created – both depends on the transported motion for the distance 2.59 million km
Please note
Many geometrical rules are unknown- the data is created depends on each other but the used rules are unknown for that the explanation is not so clear – also – sometimes the data be so strong and so obscure in the same time – let's give one example here
Pluto (4.7 km/s) moves in its rotation period (153.3 h) a distance = 2.59 million km
But the distance 2.59 million km = 7510 km (Pluto circumference) x 344
But
Jupiter needs (344 days x 2) to pass a distance = 778.6 million km = Jupiter orbital distance –
This data tells the value (344) is used by Pluto and Jupiter in two different meanings but the fact is that (one geometrical reason behind these 2 uses) but we can't see this one geometrical reason because many rules are unknown
Data No. (4)
13.1 km/s x 10921 s = 142984 km -And
4900 million km = 449197 km x 10921 km - where
13.1 km /s = Jupiter Velocity
10921 km = The Moon Circumference
142984 km = Jupiter Diameter
449197 km = Jupiter Circumference
4900 million km = Jupiter Orbital Circumference
Data No. (5)
4900 million km = 1.392 mkm x 3475 km = 406000 km x 12104 km = 384000 km x 12756 km = 363000 x 2 x 6792 km = 51118 km x 49528 km x 2 (max error 3%)
Where
4900 million km = Jupiter Orbital Circumference
1.392 million km = The Sun Diameter
3475 km = The Moon Diameter
12104 km = Venus Diameter
12756 km = The Earth Diameter
6792 km = Mars Diameter
51118 km = Uranus Diameter
49528 km = Neptune Diameter
406000 km = The Moon Orbital Apogee Radius =The Planets Diameters Total
384000 km = The Moon Orbital Distance
363000 km = The Moon Orbital Perigee Radius
378675 km = Saturn Circumference (= 406000 km/1.0725)
(1)
The data shows all planets diameters are rated with Jupiter orbital circumference -
Also the data tells the moon orbit design uses the planets diameters as measurement – means- the fact tells (the distance between the Earth and the moon at apogee radius= the planets diameter total =406000 km) this feature is only one feature of the design
Means- any analysis for the moon orbit design will show similar information because the moon orbit deign depends on the planets diameters as measurement- this is the result of the planet diameter equation effect on the moon orbit design where the equation depends on the moon motion that causes the moon orbit to be designed by the equation effect and this effect is seen in the moon orbit design uses the planets diameters as measurements to form the design.
(2)
Also we understand that Jupiter orbital circumference is used here because Jupiter designs the moon orbit by its motion for the periods (17.2 h and 53.9 h)
Shortly
The moon orbit design depends on the planets diameters total because of the planet diameter equation effect on the moon orbit design
and
Jupiter orbit is b used here as a general reference for all dimensions for the moon orbit and planets diameters and even the sun diameter because the moon orbit is defined by Jupiter motion during (17.2 h and 53.9 h)
Notice
Jupiter transports the motion to Venus and Venus transports the motion to the moon but the moon orbit design doesn't show Venus Data but Jupiter data – that because –Venus and Mercury use different language (what's time for us used for them as distance) but Jupiter data is more clear because it uses our language – to prove that- the moon orbital circumference 2.55 million km (defined by Jupiter motion for the distance 53.9 hours) is seen in Venus data as (224.7/88)= 2.55
Where
224.7 days = Venus orbital period and 88 days = Mercury orbital period
where the rate (2.55) is transported to the moon as (2.55 million km = the moon orbital circumference at apogee radius)
NOTICE
Jupiter Diameter Equation Analysis
THE EQUATIONS
Jupiter equation (10500/142984) = 13.1/(27.78 x 2π) = 0.0734 (error 2.2%)
10500 = Jupiter rotation periods number in Jupiter orbital period
142984 km = Jupiter diameter
13.1 km/s = Jupiter velocity
27.78 km/s = The Earth Moon velocity
4331 days = Jupiter orbital period (and Jupiter rotation period =9.9 hours)
Pluto equation (14178 /2390) = 27.78/ 4.7 =5.9
14178 = Pluto rotation periods number in Pluto orbital period
23908 km = Pluto diameter
27.78 km/s = The Moon velocity
4.7 km/s = Pluto velocity
90560 days = Pluto orbital period (and Pluto rotation period =153.3 hours)
(1)
The previous study explains how the equation works-
We have seen that (SV for Jupiter) = 2 (SV for Pluto)
And also (SV for Pluto) = 2π (SV for the Earth)
This discussion proved the transportation of motion among the planets
(2)
Jupiter and Pluto diameters equations use the moon velocity because the equation depends on the moon motion and Jupiter and Pluto are the equation terminals that shows the transportation of motion creates the data of the two planets to be suitable for the planet diameter equation using
(3)
Also the rule (AB =constant) for the planets diameters depend on (Jupiter diameter x Pluto diameter) that shows the data is connected between the two planets
Notice
Jupiter equation produces 0.0734 = 1/13.6
13.6 = Mars diameter equation result (10.2) x 1.3 (Jupiter orbital inclination)
And
5.9 x 4.7 (Pluto velocity) = 2 x 13.6 (error 2%)
This data shows Jupiter equation result is connected with Mars and Pluto because these are the 2 migrant planets and Jupiter tries to repair the negative effects on the solar system design resulting by the planets migration.
Notice No.(1)
Jupiter connects itself with the three inner planets (Mercury, Venus and the Earth) by the following data system
Mercury moves in its day period (176 solar days) a distance =720 million km = Mercury Jupiter distance
And
Venus Jupiter distance= 671 mkm and Venus orbital circumference =680 mkm (1.2%)
And
Earth Jupiter distance= 929 mkm and Earth orbital circumference =940 mkm (1.2%)
(the distance 929 mkm is created when the Earth and Jupiter be on 2 different sides from The Sun where 929 mkm =149.6 mkm +778.6 mkm).
And
Jupiter connects itself with the three outer planets (Saturn, Uranus and Neptune) by Jupiter motion for the distance (2.54 million km) by which Jupiter defines the period 53.9 hours to be the four planets rotation periods total
By that Jupiter made itself the central point of the solar system design.
Notice No.(2)
13.1 (km/s) x 142984 sec = 29.8 km/s x 17.2 h x 3600 = 9.7 km/s x 53.9 h x 3600 = 4.7 km/s x 400000 sec –where
13.1 km/s = Jupiter Velocity 4.7 km/s =Pluto velocity
29.8 km/s = The Earth Velocity
9.7 km/s = Saturn Velocity
142984 km= Jupiter diameter
17.2 h = Uranus Rotation Period
53.9 h = The Four Planets Rotation Periods Total
The data tells Jupiter diameter is used as measurement to define the planets diameters total- also we understand the motion is connected because
the Earth velocity = π Saturn velocity = 2π Saturn velocity
Thanks a lot – please read
Physics Nobel Prize For Imaginary Ideas!
or
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
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