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wildlyhardphilosopher-blog · 6 years ago

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Dog Training Aylesbury | Learn the Secret

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Dog Training Aylesbury | Learn the Secret

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usajobsite · 6 years ago

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Car Rental Reservationist

Virtual Desk Jobs is seeking Car Rental Reservationists for our Contact Center?s Customer Service team! Our Customer Service Representatives answer general questions, research reservations and billing, troubleshoot and resolve a variety of customer concerns, and address complaints, all while providing the highest level of service for which we?re known and our customers expect! If you? Can utilize effective problem-solving techniques to resolve customer needs with confidence and empathy Value teamwork and personal honesty and integrity Can navigate across multiple computer systems and program applications Enjoy analyzing and resolving a variety of complex issues Then this may be that outstanding opportunity you?ve been searching for! Customer service is our way of life! Our goal is to exceed our customer?s expectations and that starts with YOU! One customer, one call; one delivered promise at a time. We work hard and reward hard work! In addition to $12.85/hour, you will have the opportunity to earn bonuses based on both individual and team performance. Top performing individuals earn an additional $600/month, while top performing teams can earn up to an additional $2 more per hour, for every hour worked, during each month! Schedule Requirements: To best serve the needs of our customers, our Customer Service team is available until 10:00 pm CST offering full-time schedules with start times between 11 am ? 1:30 pm. Schedules include working weekends and do not change week-to-week. Once a schedule is assigned it is not negotiable upon completion of training. 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Equipment may arrive separately. ? *We reserve the right to verify that your PC meets or exceeds these requirements. Apply To Become A Customer Service Agent: https://virtualdeskjobs.com/join-now/- Please reference agent ID code VDJSerenaJ. Please contact us directly to discuss customer service remote job openings at 405-494-0214. Car-Rental-Reservationist from Job Portal https://www.jobisite.com/ext/617768-Car-Rental-Reservationist

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ellenarose21-blog · 6 years ago

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CARD 405 Career Development

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jobisite11 · 6 years ago

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Car Rental Reservationist

Virtual Desk Jobs is seeking Car Rental Reservationists for our Contact Center?s Customer Service team! Our Customer Service Representatives answer general questions, research reservations and billing, troubleshoot and resolve a variety of customer concerns, and address complaints, all while providing the highest level of service for which we?re known and our customers expect! If you? Can utilize effective problem-solving techniques to resolve customer needs with confidence and empathy Value teamwork and personal honesty and integrity Can navigate across multiple computer systems and program applications Enjoy analyzing and resolving a variety of complex issues Then this may be that outstanding opportunity you?ve been searching for! Customer service is our way of life! Our goal is to exceed our customer?s expectations and that starts with YOU! One customer, one call; one delivered promise at a time. We work hard and reward hard work! In addition to $12.85/hour, you will have the opportunity to earn bonuses based on both individual and team performance. Top performing individuals earn an additional $600/month, while top performing teams can earn up to an additional $2 more per hour, for every hour worked, during each month! Schedule Requirements: To best serve the needs of our customers, our Customer Service team is available until 10:00 pm CST offering full-time schedules with start times between 11 am ? 1:30 pm. Schedules include working weekends and do not change week-to-week. Once a schedule is assigned it is not negotiable upon completion of training. Responsibilities Handle multiple tasks, such as, talking with and listening to customers while accessing, reading, and inputting information into numerous applications Handle incoming calls, efficiently resolving a variety of customer service inquiries Utilize problem-solving skills to efficiently answer customer requests Maintain, at a minimum, target levels of productivity and performance Locate and interpret complex information from a number of databases Maintain a courteous and pleasant demeanor while speaking with external and internal customers Adapt to the need of individual callers Accept repetitive work tasks while providing excellent service to customers Provide timely and accurate information reflecting a customer-oriented image for the company Seek to improve job performance through self-assessment, skill development, training and goal setting Maintain a regular and reliable level of attendance and punctuality Perform miscellaneous job-related duties as assigned Qualifications Minimum 2 years of customer service experience focused on resolving customer concerns and handling difficult conversations Experience in a performance-based or metric-driven environment Call center experience preferred Experience handling help desk or escalated situations requiring problem resolution preferred Work-related experience working on a personal computer (PC), navigating through multiple computer systems and screens Permanent residence with a defined working space that is clean and quiet Ability to participate and complete mandatory training for 6 weeks, M-F, 9-5:30pm CST Ability to complete I-9 work authorization paperwork in person Must be willing to work a full-time schedule (40 hours/week), with start times between 11am-1pm (Central Time Zone), including both weekends days (Saturday & Sunday) Must be willing to accept a starting pay of $12.85/hour Must be authorized to work in the United States and not require work authorization sponsorship by our company for this position now or in the future Must be at least 18 years old Technical Qualifications: Must have a computer/PC (No MACs) with compatible OS versions: Windows 7, 8, 8.1, or Windows 10 Must have a computer USB headset with microphone Must have a separate modem Must have a router with gigabit speed connection via Ethernet cable Must have high-speed internet access provided by a cable or fiber provider (no DSL, satellite or wireless) Minimum upload speed of 2 mbps Minimum download speed of 5 mbps Use of wireless and WiFi ?air cards? is prohibited *Applicants must meet all technical qualifications at the time of application. Qualified candidates must also possess the following: Exceptional communication both verbal and written; a good telephone voice, proper English usage, and the ability to ?project? oneself over the phone are necessary Must be dependable and comfortable working independently as well as part of a team where expertise is shared and feedback is welcomed Advanced personal computing and keyboard skills Ability to rely on provided resources and quickly research responses Strong time management, organizational and problem-solving skills Strong computer navigation skills and ability to toggle between different computer screens and programs Ability to apply experience-based knowledge and leadership skills toward organizational goals Strong sense of initiative and ability to stay optimistic while working with difficult customers *You will be shipped a headset and key fob to the address provided on your application. Equipment may arrive separately. ? *We reserves the right to verify that your PC meets or exceeds these requirements. Apply To Become A Customer Service Agent: https://virtualdeskjobs.com/join-now/- Please reference agent ID code VDJGiovanieM. Please contact us directly to discuss customer service remote job openings at 405-494-0214. CarRentalReservationist from Job Portal https://www.jobisite.com/extrJobView.htm?id=411276

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jobisitejobs · 6 years ago

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Car Rental Reservationist

Virtual Desk Jobs is seeking Car Rental Reservationists for our Contact Center?s Customer Service team! Our Customer Service Representatives answer general questions, research reservations and billing, troubleshoot and resolve a variety of customer concerns, and address complaints, all while providing the highest level of service for which we?re known and our customers expect! If you? Can utilize effective problem-solving techniques to resolve customer needs with confidence and empathy Value teamwork and personal honesty and integrity Can navigate across multiple computer systems and program applications Enjoy analyzing and resolving a variety of complex issues Then this may be that outstanding opportunity you?ve been searching for! Customer service is our way of life! Our goal is to exceed our customer?s expectations and that starts with YOU! One customer, one call; one delivered promise at a time. We work hard and reward hard work! In addition to $12.85/hour, you will have the opportunity to earn bonuses based on both individual and team performance. Top performing individuals earn an additional $600/month, while top performing teams can earn up to an additional $2 more per hour, for every hour worked, during each month! Schedule Requirements: To best serve the needs of our customers, our Customer Service team is available until 10:00 pm CST offering full-time schedules with start times between 11 am ? 1:30 pm. Schedules include working weekends and do not change week-to-week. Once a schedule is assigned it is not negotiable upon completion of training. Responsibilities Handle multiple tasks, such as, talking with and listening to customers while accessing, reading, and inputting information into numerous applications Handle incoming calls, efficiently resolving a variety of customer service inquiries Utilize problem-solving skills to efficiently answer customer requests Maintain, at a minimum, target levels of productivity and performance Locate and interpret complex information from a number of databases Maintain a courteous and pleasant demeanor while speaking with external and internal customers Adapt to the need of individual callers Accept repetitive work tasks while providing excellent service to customers Provide timely and accurate information reflecting a customer-oriented image for the company Seek to improve job performance through self-assessment, skill development, training and goal setting Maintain a regular and reliable level of attendance and punctuality Perform miscellaneous job-related duties as assigned Qualifications Minimum 2 years of customer service experience focused on resolving customer concerns and handling difficult conversations Experience in a performance-based or metric-driven environment Call center experience preferred Experience handling help desk or escalated situations requiring problem resolution preferred Work-related experience working on a personal computer (PC), navigating through multiple computer systems and screens Permanent residence with a defined working space that is clean and quiet Ability to participate and complete mandatory training for 6 weeks, M-F, 9-5:30pm CST Ability to complete I-9 work authorization paperwork in person Must be willing to work a full-time schedule (40 hours/week), with start times between 11am-1pm (Central Time Zone), including both weekends days (Saturday & Sunday) Must be willing to accept a starting pay of $12.85/hour Must be authorized to work in the United States and not require work authorization sponsorship by our company for this position now or in the future Must be at least 18 years old Technical Qualifications: Must have a computer/PC (No MACs) with compatible OS versions: Windows 7, 8, 8.1, or Windows 10 Must have a computer USB headset with microphone Must have a separate modem Must have a router with gigabit speed connection via Ethernet cable Must have high-speed internet access provided by a cable or fiber provider (no DSL, satellite or wireless) Minimum upload speed of 2 mbps Minimum download speed of 5 mbps Use of wireless and WiFi ?air cards? is prohibited *Applicants must meet all technical qualifications at the time of application. Qualified candidates must also possess the following: Exceptional communication both verbal and written; a good telephone voice, proper English usage, and the ability to ?project? oneself over the phone are necessary Must be dependable and comfortable working independently as well as part of a team where expertise is shared and feedback is welcomed Advanced personal computing and keyboard skills Ability to rely on provided resources and quickly research responses Strong time management, organizational and problem-solving skills Strong computer navigation skills and ability to toggle between different computer screens and programs Ability to apply experience-based knowledge and leadership skills toward organizational goals Strong sense of initiative and ability to stay optimistic while working with difficult customers *You will be shipped a headset and key fob to the address provided on your application. Equipment may arrive separately. ? *We reserves the right to verify that your PC meets or exceeds these requirements. Apply To Become A Customer Service Agent: https://virtualdeskjobs.com/join-now/- Please reference agent ID code VDJGiovanieM. Please contact us directly to discuss customer service remote job openings at 405-494-0214. CarRentalReservationist from Job Portal https://www.jobisite.com/extrJobView.htm?id=411276

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barbarapfister-blog · 8 years ago

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MATH 533 ( Applied Managerial Statistics ) Entire Course

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(MATH 533 Week 8 Final Exam Answers)

MATH 533 ( Applied Managerial Statistics ) Final Exam Answers

MATH 533 Final Exam Set 1

(TCO D) PuttingPeople2Work has a growing business placing out-of-work MBAs. They claim they can place a client in a job in their field in less than 36 weeks. You are given the following data from a sample. Sample size: 100 Population standard deviation: 5 Sample mean: 34.2 Formulate a hypothesis test to evaluate the claim. (Points : 10) Ho: µ = 36; Ha: µ ≠ 36 Ho: µ ≥ 36; Ha: µ < 36 Ho: µ ≤ 34.2; Ha: µ > 34.2 Ho: µ > 36; Ha: µ ≤ 36

Ans. b. H0 must always have equal sign, < 36 weeks 2. (TCO B) The Republican party is interested in studying the number of republicans that might vote in a particular congressional district. Assume that the number of voters is binomially distributed by party affiliation (either republican or not republican). If 10 people show up at the polls, determine the following: Binomial distribution

0.5

P(X)

cumulative probability

0.00098

0.00977

0.01074

0.04395

0.05469

0.11719

0.17188

0.20508

0.37695

0.24609

0.62305

0.20508

0.82813

0.11719

0.94531

0.04395

0.98926

0.00977

0.99902

0.00098

1.00000

What is the probability that no more than four will be republicans? (Points : 10) 38% 12% 21% 62%

Ans. a look at x=4, cumulative probability 3. (TCO A) Company ABC had sales per month as listed below. Using the Minitab output given, determine: (A) Range (5 points); (B) Median (5 points); and (C) The range of the data that would contain 68% of the results. (5 points). Raw data: sales/month (Millions of $) 23 45 34 34 56 67 54 34 45 56 23 19 Descriptive Statistics: Sales

Variable

Total Count

Mean

StDev

Variance

Minimum

Maximum

Range

Sales

40.83

15.39

236.88

19.00

67.00

48.00

Stem-and-Leaf Display: Sales Stem-and-leaf of Sales N = 12 Leaf Unit = 1.0

444

Reference: (TCO A) Company ABC had sales per month as listed below. Using the MegaStat output given, determine: (A) Range (5 points) (B) Median (5 points) (C) The range of the data that would contain 68% of the results. (5 points)

Raw data: sales/month (Millions of $) 19 34 23 34 56 45 35 36 46 47 19 23

count 12 mean 34.75 sample variance 146.20 sample standard deviation 12.09 minimum 19 maximum 56 range 37

Stem and Leaf plot for # 1 stem unit = 10 leaf unit = 1

count

12.00000

mean

34.75000

sample variance

146.20455

sample standard deviation

12.09151

minimum

19.00000

maximum

56.00000

range

37.00000

1st quartile

23.00000

median

34.50000

3rd quartile

45.25000

interquartile range

22.25000

mode

19.00000

4. (TCO C, D) Tesla Motors needs to buy axles for their new car. They are considering using Chris Cross Manufacturing as a vendor. Tesla’s requirement is that 95% of the axles are 100 cm ± 2 cm. The following data is from a test run from Chris Cross Manufacturing. Should Tesla select them as a vendor? Explain your answer. Descriptive statistics

count

mean

99.850

sample variance

4.627

sample standard deviation

2.151

minimum

96.9

maximum

104

range

7.1

population variance

4.338

population standard deviation

2.083

standard error of the mean

0.538

tolerance interval 95.45% lower

95.548

tolerance interval 95.45% upper

104.152

margin of error

4.302

1st quartile

98.850

median

99.200

3rd quartile

100.550

interquartile range

1.700

mode

103.000

(Points : 25) Reference: Chegg Tesla Motors needs to buy axles for their new car. They are considering using Chris Cross Manufacturing as a vendor. Tesla’s requirement is that 95% of the axles are 100 cm ± 5 cm. The following data is MegaStat output from a test run from Chris Cross Manufacturing.

Descriptive statistics count: 16 mean: 99.938 sample variance: 2.313 sample standard deviation: 1.521 minimum: 97 maximum: 102.9 range: 5.9 population variance: 2.169 population standard deviation: 1.473 standard error of the mean: 0.380 tollerance interval 95.45% lower: 96.896 tolerance interval 95.45% upper: 102.979 half-width: 3.042

1st quartile: 98.900 median: 99.850 3rd quartile: 100.475 interquartile range: 1.575 mode: 98.900

Question: Should Tesla select them as a vendor? Explain your answer.

Answers (1)

· Given that,

Tesla Motors needs to buy axles for their new car. They are considering using Chris Cross Manufacturing as a vendor. Tesla’s requirement is that 95% of the axles are 100 cm ± 5 cm. The following data is MegaStat output from a test run from Chris Cross Manufacturing:

1st quartile: 98.900 median: 99.850 3rd quartile: 100.475 interquartile range: 1.575 mode: 98.900 Now, we have to construct 95% confidence interval for the data from

the Chris Cross Manufacturing

(TCO D) A PC manufacturer claims that no more than 2% of their machines are defective. In a random sample of 100 machines, it is found that 4.5% are defective. The manufacturer claims this is a fluke of the sample. At a .02 level of significance, test the manufacturer’s claim, and explain your answer.

Test and CI for One Proportion

Test of p = 0.02 vs p > 0.02

Sample

Sample p

98% Lower Bound

Z-Value

P-Value

100

0.040000

0.000000

1.43

0.077

Reference:

Set up the hypotheses:

H0: p <= 0.02

Ha: p > 0.02

This is a one tailed test, since we will only reject for high proportions.

Since we are using a 0.02 level of significance (it’s just chance that the hypotheses happen to have the same value as this), we’ll reject the null hypothesis if our P Value is less than 0.02.

The computed P value from Megastat was 0.0371.

This is higher than the significance level.

Therefore, we do not reject H0:.

We can say that the proportion is still less than or equal to 2%, and this was a fluke.

Final Page 2

1. (TCO B) The following table gives the number of visits to recreational facilities by kind and geographical region. (Points : 30)

Ans.

East

South

Midwest

West

Totals

Local Park

328

464

National Park

233

514

204

251

1202

State Park

100

526

102

793

Totals

388

1368

298

405

2459

(A) Referring to the above table, if a visitor is chosen at random, what is the probability that he or she is either from the South or from the West? (15 points) (B) Referring to the above table, given that the visitor is from the Midwest, what is the probability that he or she visited a local park? (15 points)

a. Total people = 2459

South + West = 1368 + 405 = 1773

probability — divide these:

1773/2459 = approx 0.721

Total Midwest = 298

Midwest local park = 29

Divide:

(TCO B, F) The length of time Americans exercise each week is normally distributed with a mean of 15.8 minutes and a standard deviation of 2.2 minutes

P(X≤x)

P(X≥x)

Mean

Std dev

.0146

.9854

15.8

2.2

.3581

.6419

15.8

2.2

.9910

.0090

15.8

2.2

.9999

.0001

15.8

2.2

p(lower)

p(upper)

(A) Analyze the output above to determine what percentage of Americans will exercise between 11 and 21 minutes per week. (15 points) (B) What percentage of Americans will exercise less than 15 minutes? If 1000 Americans were evaluated, how many would you expect to have exercised less than 15 minutes? (15 points) (Points : 30)

MATH 533 Final Exam Set 2

(TCO A) Seventeen salespeople reported the following number of sales calls completed last month.

72 93 82 81 82 97 102 107 119 86 88 91 83 93 73 100 102

Compute the mean, median, mode, and standard deviation, Q1, Q3, Min, and Max for the above sample data on number of sales calls per month. b. In the context of this situation, interpret the Median, Q1, and Q3. (Points : 33)

(TCO B) Cedar Home Furnishings has collected data on their customers in terms of whether they reside in an urban location or a suburban location, as well as rating the customers as either “good,” “borderline,” or “poor.” The data is below.

Urban

Suburban

Total

Good

168

228

Borderline

108

Poor

Total

120

280

400

If you choose a customer at random, then find the probability that the customer

is considered “borderline.”

(TCO B) Historically, 70% of your customers at Rodale Emporium pay for their purchases using credit cards. In a sample of 20 customers, find the probability that

exactly 14 customers will pay for their purchases using credit cards.

(TCO C) An operations analyst from an airline company has been asked to develop a fairly accurate estimate of the mean refueling and baggage handling time at a foreign airport. A random sample of 36 refueling and baggage handling times yields the following results.

Sample Size = 36 Sample Mean = 24.2 minutes Sample Standard Deviation = 4.2 minutes

Compute the 90% confidence interval for the population mean refueling and baggage time.

(TCO C) The manufacturer of a certain brand of toothpaste claims that a high percentage of dentists recommend the use of their toothpaste. A random sample of 400 dentists results in 310 recommending their toothpaste.

Compute the 99% confidence interval for the population proportion of dentists who recommend the use of this toothpaste.

(TCO D) A Ford Motor Company quality improvement team believes that its recently implemented defect reduction program has reduced the proportion of paint defects. Prior to the implementation of the program, the proportion of paint defects was .03 and had been stationary for the past 6 months. Ford selects a random sample of 2,000 cars built after the implementation of the defect reduction program. There were 45 cars with paint defects in that sample. Does the sample data provide evidence to conclude that the proportion of paint defects is now less than .03 (with a = .01)? Use the hypothesis testing procedure outlined below.

Formulate the null and alternative hypotheses.

(TCO D) A new car dealer calculates that the dealership must average more than 4.5% profit on sales of new cars. A random sample of 81 cars gives the following result.

Sample Size = 81 Sample Mean = 4.97% Sample Standard Deviation = 1.8%

Does the sample data provide evidence to conclude that the dealership averages more than 4.5% profit on sales of new cars (using a = .10)? Use the hypothesis testing procedure outlined below.

Formulate the null and alternative hypotheses.

(TCO E) Bill McFarland is a real estate broker who specializes in selling farmland in a large western state. Because Bill advises many of his clients about pricing their land, he is interested in developing a pricing formula of some type. He feels he could increase his business significantly if he could accurately determine the value of a farmer’s land. A geologist tells Bill that the soil and rock characteristics in most of the area that Bill sells do not vary much. Thus the price of land should depend greatly on acreage. Bill selects a sample of 30 plots recently sold. The data is found below (in Minitab), where X=Acreage and Y=Price ($1,000s).

PRICE

ACREAGE

PREDICT

20.0

130

40.5

250

10.2

300

100.0

30.0

182

56.5

115

41.0

10.0

18.5

30.0

25.6

122

42.0

14.0

200

70.0

13.0

21.6

6.5

145

45.0

19.2

235

80.0

250

90.0

278

95.0

118

41.0

14.0

22.0

220

81.5

235

78.0

16.0

10.0

290

100.0

Correlations: PRICE, ACREAGE Pearson correlation of PRICE and ACREAGE = 0.997 P-Value = 0.000

Regression Analysis: PRICE versus ACREAGE The regression equation is PRICE = 2.26 + 2.89 ACREAGE

Predictor Coef SE Coef T P Constant 2.257 2.231 1.01 0.320 ACREAGE 2.89202 0.04353 66.44 0.000

S = 7.21461 R-Sq = 99.4% R-Sq(adj) = 99.3%

Analysis of Variance

Source DF SS MS F P Regression 1 229757 229757 4414.11 0.000 Residual Error 28 1457 52 Total 29 231215

Predicted Values for New Observations

New Obs Fit SE Fit 95% CI 95% PI 1 146.86 1.37 (144.05, 149.66) (131.82, 161.90) 2 725.26 9.18 (706.46, 744.06) (701.35, 749.17)XX

XX denotes a point that is an extreme outlier in the predictors.

Values of Predictors for New Observations

New Obs ACREAGE 1 50 2 250

Analyze the above output to determine the regression equation.

(TCO E) An insurance firm wishes to study the relationship between driving experience (X1, in years), number of driving violations in the past three years (X2), and current monthly auto insurance premium (Y). A sample of 12 insured drivers is selected at random. The data is given below (in MINITAB):

Predict X1

Predict X2

050

060

Regression Analysis: Y versus X1, X2 The regression equation is Y = 55.1 – 1.37 X1 + 8.05 X2

Predictor Coef SE Coef T P Constant 55.138 7.309 7.54 0.000 X1 -1.3736 0.4885 -2.81 0.020 X2 8.053 1.307 6.16 0.000

S = 6.07296 R-Sq = 93.1% R-Sq(adj) = 91.6%

Analysis of Variance

Source DF SS MS F P Regression 2 4490.3 2245.2 60.88 0.000 Residual Error 9 331.9 36.9 Total 11 4822.3

Predicted Values for New Observations

New Obs Fit SE Fit 95% CI 95% PI 1 52.20 2.91 (45.62, 58.79) (36.97, 67.44)

Values of Predictors for New Observations

New Obs X1 X2 1 8.00 1.00

Correlations: Y, X1, X2 Y X1 X1 -0.800 0.002

X2 0.933 -0.660 0.000 0.020

Cell Contents: Pearson correlation P-Value

Analyze the above output to determine the multiple regression equation.

MATH 533 Final Exam Set 3

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#MATH 533 ( Applied Managerial Statistics ) Entire Course

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MATH 533 ( Applied Managerial Statistics ) Entire Course

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(MATH 533 Week 8 Final Exam Answers)

MATH 533 ( Applied Managerial Statistics ) Final Exam Answers

MATH 533 Final Exam Set 1

0.5

P(X)

cumulative probability

0.00098

0.00977

0.01074

0.04395

0.05469

0.11719

0.17188

0.20508

0.37695

0.24609

0.62305

0.20508

0.82813

0.11719

0.94531

0.04395

0.98926

0.00977

0.99902

0.00098

1.00000

What is the probability that no more than four will be republicans? (Points : 10) 38% 12% 21% 62%

Variable

Total Count

Mean

StDev

Variance

Minimum

Maximum

Range

Sales

40.83

15.39

236.88

19.00

67.00

48.00

Stem-and-Leaf Display: Sales Stem-and-leaf of Sales N = 12 Leaf Unit = 1.0

444

Raw data: sales/month (Millions of $) 19 34 23 34 56 45 35 36 46 47 19 23

count 12 mean 34.75 sample variance 146.20 sample standard deviation 12.09 minimum 19 maximum 56 range 37

Stem and Leaf plot for # 1 stem unit = 10 leaf unit = 1

count

12.00000

mean

34.75000

sample variance

146.20455

sample standard deviation

12.09151

minimum

19.00000

maximum

56.00000

range

37.00000

1st quartile

23.00000

median

34.50000

3rd quartile

45.25000

interquartile range

22.25000

mode

19.00000

count

mean

99.850

sample variance

4.627

sample standard deviation

2.151

minimum

96.9

maximum

104

range

7.1

population variance

4.338

population standard deviation

2.083

standard error of the mean

0.538

tolerance interval 95.45% lower

95.548

tolerance interval 95.45% upper

104.152

margin of error

4.302

1st quartile

98.850

median

99.200

3rd quartile

100.550

interquartile range

1.700

mode

103.000

1st quartile: 98.900 median: 99.850 3rd quartile: 100.475 interquartile range: 1.575 mode: 98.900

Question: Should Tesla select them as a vendor? Explain your answer.

Answers (1)

· Given that,

1st quartile: 98.900 median: 99.850 3rd quartile: 100.475 interquartile range: 1.575 mode: 98.900 Now, we have to construct 95% confidence interval for the data from

the Chris Cross Manufacturing

Test and CI for One Proportion

Test of p = 0.02 vs p > 0.02

Sample

Sample p

98% Lower Bound

Z-Value

P-Value

100

0.040000

0.000000

1.43

0.077

Reference:

Set up the hypotheses:

H0: p <= 0.02

Ha: p > 0.02

This is a one tailed test, since we will only reject for high proportions.

Since we are using a 0.02 level of significance (it’s just chance that the hypotheses happen to have the same value as this), we’ll reject the null hypothesis if our P Value is less than 0.02.

The computed P value from Megastat was 0.0371.

This is higher than the significance level.

Therefore, we do not reject H0:.

We can say that the proportion is still less than or equal to 2%, and this was a fluke.

Final Page 2

1. (TCO B) The following table gives the number of visits to recreational facilities by kind and geographical region. (Points : 30)

Ans.

East

South

Midwest

West

Totals

Local Park

328

464

National Park

233

514

204

251

1202

State Park

100

526

102

793

Totals

388

1368

298

405

2459

a. Total people = 2459

South + West = 1368 + 405 = 1773

probability — divide these:

1773/2459 = approx 0.721

Total Midwest = 298

Midwest local park = 29

Divide:

(TCO B, F) The length of time Americans exercise each week is normally distributed with a mean of 15.8 minutes and a standard deviation of 2.2 minutes

P(X≤x)

P(X≥x)

Mean

Std dev

.0146

.9854

15.8

2.2

.3581

.6419

15.8

2.2

.9910

.0090

15.8

2.2

.9999

.0001

15.8

2.2

p(lower)

p(upper)

MATH 533 Final Exam Set 2

(TCO A) Seventeen salespeople reported the following number of sales calls completed last month.

72 93 82 81 82 97 102 107 119 86 88 91 83 93 73 100 102

Urban

Suburban

Total

Good

168

228

Borderline

108

Poor

Total

120

280

400

If you choose a customer at random, then find the probability that the customer

is considered “borderline.”

(TCO B) Historically, 70% of your customers at Rodale Emporium pay for their purchases using credit cards. In a sample of 20 customers, find the probability that

exactly 14 customers will pay for their purchases using credit cards.

Sample Size = 36 Sample Mean = 24.2 minutes Sample Standard Deviation = 4.2 minutes

Compute the 90% confidence interval for the population mean refueling and baggage time.

Compute the 99% confidence interval for the population proportion of dentists who recommend the use of this toothpaste.

Formulate the null and alternative hypotheses.

(TCO D) A new car dealer calculates that the dealership must average more than 4.5% profit on sales of new cars. A random sample of 81 cars gives the following result.

Sample Size = 81 Sample Mean = 4.97% Sample Standard Deviation = 1.8%

Does the sample data provide evidence to conclude that the dealership averages more than 4.5% profit on sales of new cars (using a = .10)? Use the hypothesis testing procedure outlined below.

Formulate the null and alternative hypotheses.

PRICE

ACREAGE

PREDICT

20.0

130

40.5

250

10.2

300

100.0

30.0

182

56.5

115

41.0

10.0

18.5

30.0

25.6

122

42.0

14.0

200

70.0

13.0

21.6

6.5

145

45.0

19.2

235

80.0

250

90.0

278

95.0

118

41.0

14.0

22.0

220

81.5

235

78.0

16.0

10.0

290

100.0

Correlations: PRICE, ACREAGE Pearson correlation of PRICE and ACREAGE = 0.997 P-Value = 0.000

Regression Analysis: PRICE versus ACREAGE The regression equation is PRICE = 2.26 + 2.89 ACREAGE

Predictor Coef SE Coef T P Constant 2.257 2.231 1.01 0.320 ACREAGE 2.89202 0.04353 66.44 0.000

S = 7.21461 R-Sq = 99.4% R-Sq(adj) = 99.3%

Analysis of Variance

Source DF SS MS F P Regression 1 229757 229757 4414.11 0.000 Residual Error 28 1457 52 Total 29 231215

Predicted Values for New Observations

New Obs Fit SE Fit 95% CI 95% PI 1 146.86 1.37 (144.05, 149.66) (131.82, 161.90) 2 725.26 9.18 (706.46, 744.06) (701.35, 749.17)XX

XX denotes a point that is an extreme outlier in the predictors.

Values of Predictors for New Observations

New Obs ACREAGE 1 50 2 250

Analyze the above output to determine the regression equation.

Predict X1

Predict X2

050

060

Regression Analysis: Y versus X1, X2 The regression equation is Y = 55.1 – 1.37 X1 + 8.05 X2

Predictor Coef SE Coef T P Constant 55.138 7.309 7.54 0.000 X1 -1.3736 0.4885 -2.81 0.020 X2 8.053 1.307 6.16 0.000

S = 6.07296 R-Sq = 93.1% R-Sq(adj) = 91.6%

Analysis of Variance

Source DF SS MS F P Regression 2 4490.3 2245.2 60.88 0.000 Residual Error 9 331.9 36.9 Total 11 4822.3

Predicted Values for New Observations

New Obs Fit SE Fit 95% CI 95% PI 1 52.20 2.91 (45.62, 58.79) (36.97, 67.44)

Values of Predictors for New Observations

New Obs X1 X2 1 8.00 1.00

Correlations: Y, X1, X2 Y X1 X1 -0.800 0.002

X2 0.933 -0.660 0.000 0.020

Cell Contents: Pearson correlation P-Value

Analyze the above output to determine the multiple regression equation.

MATH 533 Final Exam Set 3

MATH 533 Final Exam Set 4

#MATH 533 ( Applied Managerial Statistics ) Entire Course

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MATH 533 ( Applied Managerial Statistics ) Entire Course

Follow Below Link to Download Tutorial

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(MATH 533 Week 7) MATH 533 Week 7 Course Project – Part C (SALESCALL Inc.) MATH 533 Week 7 Graded Discussion Topics

(MATH 533 Week 8 Final Exam Answers)

MATH 533 ( Applied Managerial Statistics ) Final Exam Answers

MATH 533 Final Exam Set 1

0.5

P(X)

cumulative probability

0.00098

0.00977

0.01074

0.04395

0.05469

0.11719

0.17188

0.20508

0.37695

0.24609

0.62305

0.20508

0.82813

0.11719

0.94531

0.04395

0.98926

0.00977

0.99902

0.00098

1.00000

What is the probability that no more than four will be republicans? (Points : 10) 38% 12% 21% 62%

Variable

Total Count

Mean

StDev

Variance

Minimum

Maximum

Range

Sales

40.83

15.39

236.88

19.00

67.00

48.00

Stem-and-Leaf Display: Sales Stem-and-leaf of Sales N = 12 Leaf Unit = 1.0

444

Raw data: sales/month (Millions of $) 19 34 23 34 56 45 35 36 46 47 19 23

count 12 mean 34.75 sample variance 146.20 sample standard deviation 12.09 minimum 19 maximum 56 range 37

Stem and Leaf plot for # 1 stem unit = 10 leaf unit = 1

count

12.00000

mean

34.75000

sample variance

146.20455

sample standard deviation

12.09151

minimum

19.00000

maximum

56.00000

range

37.00000

1st quartile

23.00000

median

34.50000

3rd quartile

45.25000

interquartile range

22.25000

mode

19.00000

count

mean

99.850

sample variance

4.627

sample standard deviation

2.151

minimum

96.9

maximum

104

range

7.1

population variance

4.338

population standard deviation

2.083

standard error of the mean

0.538

tolerance interval 95.45% lower

95.548

tolerance interval 95.45% upper

104.152

margin of error

4.302

1st quartile

98.850

median

99.200

3rd quartile

100.550

interquartile range

1.700

mode

103.000

1st quartile: 98.900 median: 99.850 3rd quartile: 100.475 interquartile range: 1.575 mode: 98.900

Question: Should Tesla select them as a vendor? Explain your answer.

Answers (1)

· Given that,

1st quartile: 98.900 median: 99.850 3rd quartile: 100.475 interquartile range: 1.575 mode: 98.900 Now, we have to construct 95% confidence interval for the data from

the Chris Cross Manufacturing

Test and CI for One Proportion

Test of p = 0.02 vs p > 0.02

Sample

Sample p

98% Lower Bound

Z-Value

P-Value

100

0.040000

0.000000

1.43

0.077

Reference:

Set up the hypotheses:

H0: p <= 0.02

Ha: p > 0.02

This is a one tailed test, since we will only reject for high proportions.

Since we are using a 0.02 level of significance (it’s just chance that the hypotheses happen to have the same value as this), we’ll reject the null hypothesis if our P Value is less than 0.02.

The computed P value from Megastat was 0.0371.

This is higher than the significance level.

Therefore, we do not reject H0:.

We can say that the proportion is still less than or equal to 2%, and this was a fluke.

Final Page 2

1. (TCO B) The following table gives the number of visits to recreational facilities by kind and geographical region. (Points : 30)

Ans.

East

South

Midwest

West

Totals

Local Park

328

464

National Park

233

514

204

251

1202

State Park

100

526

102

793

Totals

388

1368

298

405

2459

a. Total people = 2459

South + West = 1368 + 405 = 1773

probability — divide these:

1773/2459 = approx 0.721

Total Midwest = 298

Midwest local park = 29

Divide:

(TCO B, F) The length of time Americans exercise each week is normally distributed with a mean of 15.8 minutes and a standard deviation of 2.2 minutes

P(X≤x)

P(X≥x)

Mean

Std dev

.0146

.9854

15.8

2.2

.3581

.6419

15.8

2.2

.9910

.0090

15.8

2.2

.9999

.0001

15.8

2.2

p(lower)

p(upper)

MATH 533 Final Exam Set 2

(TCO A) Seventeen salespeople reported the following number of sales calls completed last month.

72 93 82 81 82 97 102 107 119 86 88 91 83 93 73 100 102

Urban

Suburban

Total

Good

168

228

Borderline

108

Poor

Total

120

280

400

If you choose a customer at random, then find the probability that the customer

is considered “borderline.”

(TCO B) Historically, 70% of your customers at Rodale Emporium pay for their purchases using credit cards. In a sample of 20 customers, find the probability that

exactly 14 customers will pay for their purchases using credit cards.

Sample Size = 36 Sample Mean = 24.2 minutes Sample Standard Deviation = 4.2 minutes

Compute the 90% confidence interval for the population mean refueling and baggage time.

Compute the 99% confidence interval for the population proportion of dentists who recommend the use of this toothpaste.

Formulate the null and alternative hypotheses.

(TCO D) A new car dealer calculates that the dealership must average more than 4.5% profit on sales of new cars. A random sample of 81 cars gives the following result.

Sample Size = 81 Sample Mean = 4.97% Sample Standard Deviation = 1.8%

Does the sample data provide evidence to conclude that the dealership averages more than 4.5% profit on sales of new cars (using a = .10)? Use the hypothesis testing procedure outlined below.

Formulate the null and alternative hypotheses.

PRICE

ACREAGE

PREDICT

20.0

130

40.5

250

10.2

300

100.0

30.0

182

56.5

115

41.0

10.0

18.5

30.0

25.6

122

42.0

14.0

200

70.0

13.0

21.6

6.5

145

45.0

19.2

235

80.0

250

90.0

278

95.0

118

41.0

14.0

22.0

220

81.5

235

78.0

16.0

10.0

290

100.0

Correlations: PRICE, ACREAGE Pearson correlation of PRICE and ACREAGE = 0.997 P-Value = 0.000

Regression Analysis: PRICE versus ACREAGE The regression equation is PRICE = 2.26 + 2.89 ACREAGE

Predictor Coef SE Coef T P Constant 2.257 2.231 1.01 0.320 ACREAGE 2.89202 0.04353 66.44 0.000

S = 7.21461 R-Sq = 99.4% R-Sq(adj) = 99.3%

Analysis of Variance

Source DF SS MS F P Regression 1 229757 229757 4414.11 0.000 Residual Error 28 1457 52 Total 29 231215

Predicted Values for New Observations

New Obs Fit SE Fit 95% CI 95% PI 1 146.86 1.37 (144.05, 149.66) (131.82, 161.90) 2 725.26 9.18 (706.46, 744.06) (701.35, 749.17)XX

XX denotes a point that is an extreme outlier in the predictors.

Values of Predictors for New Observations

New Obs ACREAGE 1 50 2 250

Analyze the above output to determine the regression equation.

Predict X1

Predict X2

050

060

Regression Analysis: Y versus X1, X2 The regression equation is Y = 55.1 – 1.37 X1 + 8.05 X2

Predictor Coef SE Coef T P Constant 55.138 7.309 7.54 0.000 X1 -1.3736 0.4885 -2.81 0.020 X2 8.053 1.307 6.16 0.000

S = 6.07296 R-Sq = 93.1% R-Sq(adj) = 91.6%

Analysis of Variance

Source DF SS MS F P Regression 2 4490.3 2245.2 60.88 0.000 Residual Error 9 331.9 36.9 Total 11 4822.3

Predicted Values for New Observations

New Obs Fit SE Fit 95% CI 95% PI 1 52.20 2.91 (45.62, 58.79) (36.97, 67.44)

Values of Predictors for New Observations

New Obs X1 X2 1 8.00 1.00

Correlations: Y, X1, X2 Y X1 X1 -0.800 0.002

X2 0.933 -0.660 0.000 0.020

Cell Contents: Pearson correlation P-Value

Analyze the above output to determine the multiple regression equation.

MATH 533 Final Exam Set 3

MATH 533 Final Exam Set 4

#MATH 533 ( Applied Managerial Statistics ) Entire Course

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MATH 533 ( Applied Managerial Statistics ) Full Course 2016

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(MATH 533 Applied Managerial Statistics – DeVry)

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MATH 533 ( Applied Managerial Statistics ) Final Exam Answers

MATH 533 Final Exam Set 1

0.5

P(X)

cumulative probability

00.00098

0.00098

0.00977

0.01074

0.04395

0.05469

0.11719

0.17188

0.20508

0.37695

0.24609

0.62305

0.20508

0.82813

0.11719

0.94531

0.04395

0.98926

0.00977

0.99902

0.00098

1.00000

What is the probability that no more than four will be republicans? (Points : 10) 38% 12% 21% 62%Ans. a look at x=4, cumulative probability 3. (TCO A) Company ABC had sales per month as listed below. Using the Minitab output given, determine: (A) Range (5 points); (B) Median (5 points); and (C) The range of the data that would contain 68% of the results. (5 points). Raw data: sales/month (Millions of $) 23 45 34 34 56 67 54 34 45 56 23 19 Descriptive Statistics: Sales

Variable

Total Count

Mean

StDev

Variance

Minimum

Maximum

Range

Sales

40.83

15.39

236.88

19.00

67.00

48.00

Stem-and-Leaf Display: Sales Stem-and-leaf of Sales N = 12 Leaf Unit = 1.0

444

Raw data: sales/month (Millions of $) 19 34 23 34 56 45 35 36 46 47 19 23

count 12 mean 34.75 sample variance 146.20 sample standard deviation 12.09 minimum 19 maximum 56 range 37

Stem and Leaf plot for # 1 stem unit = 10 leaf unit = 1

count

12.00000

mean

34.75000

sample variance

146.20455

sample standard deviation

12.09151

minimum

19.00000

maximum

56.00000

range

37.00000

1st quartile

23.00000

median

34.50000

3rd quartile

45.25000

interquartile range

22.25000

mode

19.00000

count

mean

99.850

sample variance

4.627

sample standard deviation

2.151

minimum

96.9

maximum

104

range

7.1

population variance

4.338

population standard deviation

2.083

standard error of the mean

0.538

tolerance interval 95.45% lower

95.548

tolerance interval 95.45% upper

104.152

margin of error

4.302

1st quartile

98.850

median

99.200

3rd quartile

100.550

interquartile range

1.700

mode

103.000

1st quartile: 98.900 median: 99.850 3rd quartile: 100.475 interquartile range: 1.575 mode: 98.900

Question: Should Tesla select them as a vendor? Explain your answer.

Answers (1)

· Given that,

1st quartile: 98.900 median: 99.850 3rd quartile: 100.475 interquartile range: 1.575 mode: 98.900 Now, we have to construct 95% confidence interval for the data from

the Chris Cross Manufacturing

Test and CI for One Proportion

Test of p = 0.02 vs p > 0.02

Sample

Sample p

98% Lower Bound

Z-Value

P-Value

100

0.040000

0.000000

1.43

0.077

Reference:

Set up the hypotheses:

H0: p <= 0.02

Ha: p > 0.02

This is a one tailed test, since we will only reject for high proportions.

Since we are using a 0.02 level of significance (it’s just chance that the hypotheses happen to have the same value as this), we’ll reject the null hypothesis if our P Value is less than 0.02.

The computed P value from Megastat was 0.0371.

This is higher than the significance level.

Therefore, we do not reject H0:.

We can say that the proportion is still less than or equal to 2%, and this was a fluke.

Final Page 2

1. (TCO B) The following table gives the number of visits to recreational facilities by kind and geographical region. (Points : 30)Ans.

East

South

Midwest

West

Totals

Local Park

328

464

National Park

233

514

204

251

1202

State Park

100

526

102

793

Totals

388

1368

298

405

2459

a. Total people = 2459

South + West = 1368 + 405 = 1773

probability — divide these:

1773/2459 = approx 0.721

Total Midwest = 298

Midwest local park = 29

Divide:

(TCO B, F) The length of time Americans exercise each week is normally distributed with a mean of 15.8 minutes and a standard deviation of 2.2 minutes

P(X≤x)

P(X≥x)

Mean

Std dev

.0146

.9854

15.8

2.2

.3581

.6419

15.8

2.2

.9910

.0090

15.8

2.2

.9999

.0001

15.8

2.2

p(lower)

p(upper)

MATH 533 Final Exam Set 2

(TCO A) Seventeen salespeople reported the following number of sales calls completed last month.

72 93 82 81 82 97 102 107 119 86 88 91 83 93 73 100 102

Urban

Suburban

Total

Good

168

228

Borderline

108

Poor

Total

120

280

400

If you choose a customer at random, then find the probability that the customer

is considered “borderline.”

(TCO B) Historically, 70% of your customers at Rodale Emporium pay for their purchases using credit cards. In a sample of 20 customers, find the probability that

exactly 14 customers will pay for their purchases using credit cards.

Sample Size = 36 Sample Mean = 24.2 minutes Sample Standard Deviation = 4.2 minutes

Compute the 90% confidence interval for the population mean refueling and baggage time.

Compute the 99% confidence interval for the population proportion of dentists who recommend the use of this toothpaste.

Formulate the null and alternative hypotheses.

(TCO D) A new car dealer calculates that the dealership must average more than 4.5% profit on sales of new cars. A random sample of 81 cars gives the following result.

Sample Size = 81 Sample Mean = 4.97% Sample Standard Deviation = 1.8%

Does the sample data provide evidence to conclude that the dealership averages more than 4.5% profit on sales of new cars (using a = .10)? Use the hypothesis testing procedure outlined below.

Formulate the null and alternative hypotheses.

PRICE

ACREAGE

PREDICT

20.0

130

40.5

250

10.2

300

100.0

30.0

182

56.5

115

41.0

10.0

18.5

30.0

25.6

122

42.0

14.0

200

70.0

13.0

21.6

6.5

145

45.0

19.2

235

80.0

250

90.0

278

95.0

118

41.0

14.0

22.0

220

81.5

235

78.0

16.0

10.0

290

100.0

Correlations: PRICE, ACREAGE Pearson correlation of PRICE and ACREAGE = 0.997 P-Value = 0.000

Regression Analysis: PRICE versus ACREAGE The regression equation is PRICE = 2.26 + 2.89 ACREAGE

Predictor Coef SE Coef T P Constant 2.257 2.231 1.01 0.320 ACREAGE 2.89202 0.04353 66.44 0.000

S = 7.21461 R-Sq = 99.4% R-Sq(adj) = 99.3%

Analysis of Variance

Source DF SS MS F P Regression 1 229757 229757 4414.11 0.000 Residual Error 28 1457 52 Total 29 231215

Predicted Values for New Observations

New Obs Fit SE Fit 95% CI 95% PI 1 146.86 1.37 (144.05, 149.66) (131.82, 161.90) 2 725.26 9.18 (706.46, 744.06) (701.35, 749.17)XX

XX denotes a point that is an extreme outlier in the predictors.

Values of Predictors for New Observations

New Obs ACREAGE 1 50 2 250

Analyze the above output to determine the regression equation.

Predict X1

Predict X2

050

060

Regression Analysis: Y versus X1, X2 The regression equation is Y = 55.1 – 1.37 X1 + 8.05 X2

Predictor Coef SE Coef T P Constant 55.138 7.309 7.54 0.000 X1 -1.3736 0.4885 -2.81 0.020 X2 8.053 1.307 6.16 0.000

S = 6.07296 R-Sq = 93.1% R-Sq(adj) = 91.6%

Analysis of Variance

Source DF SS MS F P Regression 2 4490.3 2245.2 60.88 0.000 Residual Error 9 331.9 36.9 Total 11 4822.3

Predicted Values for New Observations

New Obs Fit SE Fit 95% CI 95% PI 1 52.20 2.91 (45.62, 58.79) (36.97, 67.44)

Values of Predictors for New Observations

New Obs X1 X2 1 8.00 1.00

Correlations: Y, X1, X2 Y X1 X1 -0.800 0.002

X2 0.933 -0.660 0.000 0.020

Cell Contents: Pearson correlation P-Value

Analyze the above output to determine the multiple regression equation.

MATH 533 Final Exam Set 3

MATH 533 Final Exam Set 4

#MATH 533 ( Applied Managerial Statistics ) Full Course 2016

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kennethboettcher-blog · 8 years ago

Text

MATH 533 ( Applied Managerial Statistics ) Entire Course

Follow Below Link to Download Tutorial

https://homeworklance.com/downloads/math-533-applied-managerial-statistics-entire-course/

For More Information Visit Our Website ( https://homeworklance.com/ )

Email us At: [email protected] or [email protected]

(MATH 533 Applied Managerial Statistics – DeVry)

(MATH 533 Week 1) MATH 533 Week 1 Homework Problems (MyStatLab) MATH 533 Week 1 Graded Discussion Topics MATH 533 Week 1 Quiz

(MATH 533 Week 2) MATH 533 Week 2 Homework Problems (MyStatLab) MATH 533 Week 2 Graded Discussion Topics MATH 533 Week 2 Course Project – Part A (SALESCALL Inc.)

(MATH 533 Week 3) MATH 533 Week 3 Homework Problems (MyStatLab) MATH 533 Week 3 Graded Discussion Topics

(MATH 533 Week 4) MATH 533 Week 4 Homework Problems (MyStatLab) MATH 533 Week 4 Graded Discussion Topics

(MATH 533 Week 5) MATH 533 Week 5 Homework Problems (MyStatLab) MATH 533 Week 5 Quiz MATH 533 Week 5 Graded Discussion Topics

(MATH 533 Week 6) MATH 533 Week 6 Homework��Problems (MyStatLab) MATH 533 Week 6 Graded Discussion Topics MATH 533 Week 6 Course Project – Part B (SALESCALL Inc.)

(MATH 533 Week 7) MATH 533 Week 7 Course Project – Part C (SALESCALL Inc.) MATH 533 Week 7 Graded Discussion Topics

(MATH 533 Week 8 Final Exam Answers)

MATH 533 ( Applied Managerial Statistics ) Final Exam Answers

MATH 533 Final Exam Set 1

0.5

P(X)

cumulative probability

0.00098

0.00977

0.01074

0.04395

0.05469

0.11719

0.17188

0.20508

0.37695

0.24609

0.62305

0.20508

0.82813

0.11719

0.94531

0.04395

0.98926

0.00977

0.99902

0.00098

1.00000

What is the probability that no more than four will be republicans? (Points : 10) 38% 12% 21% 62%

Variable

Total Count

Mean

StDev

Variance

Minimum

Maximum

Range

Sales

40.83

15.39

236.88

19.00

67.00

48.00

Stem-and-Leaf Display: Sales Stem-and-leaf of Sales N = 12 Leaf Unit = 1.0

444

Raw data: sales/month (Millions of $) 19 34 23 34 56 45 35 36 46 47 19 23

count 12 mean 34.75 sample variance 146.20 sample standard deviation 12.09 minimum 19 maximum 56 range 37

Stem and Leaf plot for # 1 stem unit = 10 leaf unit = 1

count

12.00000

mean

34.75000

sample variance

146.20455

sample standard deviation

12.09151

minimum

19.00000

maximum

56.00000

range

37.00000

1st quartile

23.00000

median

34.50000

3rd quartile

45.25000

interquartile range

22.25000

mode

19.00000

count

mean

99.850

sample variance

4.627

sample standard deviation

2.151

minimum

96.9

maximum

104

range

7.1

population variance

4.338

population standard deviation

2.083

standard error of the mean

0.538

tolerance interval 95.45% lower

95.548

tolerance interval 95.45% upper

104.152

margin of error

4.302

1st quartile

98.850

median

99.200

3rd quartile

100.550

interquartile range

1.700

mode

103.000

1st quartile: 98.900 median: 99.850 3rd quartile: 100.475 interquartile range: 1.575 mode: 98.900

Question: Should Tesla select them as a vendor? Explain your answer.

Answers (1)

· Given that,

1st quartile: 98.900 median: 99.850 3rd quartile: 100.475 interquartile range: 1.575 mode: 98.900 Now, we have to construct 95% confidence interval for the data from

the Chris Cross Manufacturing

Test and CI for One Proportion

Test of p = 0.02 vs p > 0.02

Sample

Sample p

98% Lower Bound

Z-Value

P-Value

100

0.040000

0.000000

1.43

0.077

Reference:

Set up the hypotheses:

H0: p <= 0.02

Ha: p > 0.02

This is a one tailed test, since we will only reject for high proportions.

Since we are using a 0.02 level of significance (it’s just chance that the hypotheses happen to have the same value as this), we’ll reject the null hypothesis if our P Value is less than 0.02.

The computed P value from Megastat was 0.0371.

This is higher than the significance level.

Therefore, we do not reject H0:.

We can say that the proportion is still less than or equal to 2%, and this was a fluke.

Final Page 2

1. (TCO B) The following table gives the number of visits to recreational facilities by kind and geographical region. (Points : 30)

Ans.

East

South

Midwest

West

Totals

Local Park

328

464

National Park

233

514

204

251

1202

State Park

100

526

102

793

Totals

388

1368

298

405

2459

a. Total people = 2459

South + West = 1368 + 405 = 1773

probability — divide these:

1773/2459 = approx 0.721

Total Midwest = 298

Midwest local park = 29

Divide:

(TCO B, F) The length of time Americans exercise each week is normally distributed with a mean of 15.8 minutes and a standard deviation of 2.2 minutes

P(X≤x)

P(X≥x)

Mean

Std dev

.0146

.9854

15.8

2.2

.3581

.6419

15.8

2.2

.9910

.0090

15.8

2.2

.9999

.0001

15.8

2.2

p(lower)

p(upper)

MATH 533 Final Exam Set 2

(TCO A) Seventeen salespeople reported the following number of sales calls completed last month.

72 93 82 81 82 97 102 107 119 86 88 91 83 93 73 100 102

Urban

Suburban

Total

Good

168

228

Borderline

108

Poor

Total

120

280

400

If you choose a customer at random, then find the probability that the customer

is considered “borderline.”

(TCO B) Historically, 70% of your customers at Rodale Emporium pay for their purchases using credit cards. In a sample of 20 customers, find the probability that

exactly 14 customers will pay for their purchases using credit cards.

Sample Size = 36 Sample Mean = 24.2 minutes Sample Standard Deviation = 4.2 minutes

Compute the 90% confidence interval for the population mean refueling and baggage time.

Compute the 99% confidence interval for the population proportion of dentists who recommend the use of this toothpaste.

Formulate the null and alternative hypotheses.

(TCO D) A new car dealer calculates that the dealership must average more than 4.5% profit on sales of new cars. A random sample of 81 cars gives the following result.

Sample Size = 81 Sample Mean = 4.97% Sample Standard Deviation = 1.8%

Does the sample data provide evidence to conclude that the dealership averages more than 4.5% profit on sales of new cars (using a = .10)? Use the hypothesis testing procedure outlined below.

Formulate the null and alternative hypotheses.

PRICE

ACREAGE

PREDICT

20.0

130

40.5

250

10.2

300

100.0

30.0

182

56.5

115

41.0

10.0

18.5

30.0

25.6

122

42.0

14.0

200

70.0

13.0

21.6

6.5

145

45.0

19.2

235

80.0

250

90.0

278

95.0

118

41.0

14.0

22.0

220

81.5

235

78.0

16.0

10.0

290

100.0

Correlations: PRICE, ACREAGE Pearson correlation of PRICE and ACREAGE = 0.997 P-Value = 0.000

Regression Analysis: PRICE versus ACREAGE The regression equation is PRICE = 2.26 + 2.89 ACREAGE

Predictor Coef SE Coef T P Constant 2.257 2.231 1.01 0.320 ACREAGE 2.89202 0.04353 66.44 0.000

S = 7.21461 R-Sq = 99.4% R-Sq(adj) = 99.3%

Analysis of Variance

Source DF SS MS F P Regression 1 229757 229757 4414.11 0.000 Residual Error 28 1457 52 Total 29 231215

Predicted Values for New Observations

New Obs Fit SE Fit 95% CI 95% PI 1 146.86 1.37 (144.05, 149.66) (131.82, 161.90) 2 725.26 9.18 (706.46, 744.06) (701.35, 749.17)XX

XX denotes a point that is an extreme outlier in the predictors.

Values of Predictors for New Observations

New Obs ACREAGE 1 50 2 250

Analyze the above output to determine the regression equation.

Predict X1

Predict X2

050

060

Regression Analysis: Y versus X1, X2 The regression equation is Y = 55.1 – 1.37 X1 + 8.05 X2

Predictor Coef SE Coef T P Constant 55.138 7.309 7.54 0.000 X1 -1.3736 0.4885 -2.81 0.020 X2 8.053 1.307 6.16 0.000

S = 6.07296 R-Sq = 93.1% R-Sq(adj) = 91.6%

Analysis of Variance

Source DF SS MS F P Regression 2 4490.3 2245.2 60.88 0.000 Residual Error 9 331.9 36.9 Total 11 4822.3

Predicted Values for New Observations

New Obs Fit SE Fit 95% CI 95% PI 1 52.20 2.91 (45.62, 58.79) (36.97, 67.44)

Values of Predictors for New Observations

New Obs X1 X2 1 8.00 1.00

Correlations: Y, X1, X2 Y X1 X1 -0.800 0.002

X2 0.933 -0.660 0.000 0.020

Cell Contents: Pearson correlation P-Value

Analyze the above output to determine the multiple regression equation.

MATH 533 Final Exam Set 3

MATH 533 Final Exam Set 4

#MATH 533 ( Applied Managerial Statistics ) Entire Course

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oassignment · 6 years ago

Link

CARD 405 Week 3 Assignment, Crafting Your Brand Message

1) Start by identifying your three most important strengths. In the context of your target job title (see examples below). Write a sentence about these three unique abilities and strengths

2) Add a sentence that connects your strength with an important opportunity in your industry. What benefit or value do you bring to an organization? Which challenge or pain point do you relieve? Write a sentence about the problem you solve.

3) Now, in one sentence, communicate your aspirations for your future. What exactly do you want to do? Be specific.

4) Finally, support all of this with your accomplishments; include the results you’ve produced. Share a statement or two about what makes you the best at what you do.

CARD 405 Week 3 Discussion 1,

Marketing Yourself

In Career Focus: A Personal Job Search Guide, Martucci Lamarre (2006) suggests that if we want to realize our job dreams, we need to think about ourselves as products to be marketed, and in order to do this, we need to contextualize ourselves within the five Ps of marketing: product, price, place, presentation, and promotion (p. 4). Please reflect and respond to the following questions taken from our textbook. What exactly is your product and how is it different from (or better than) other similar products?

Where will you sell your product?

Who are the potential buyers of the product and how does that price compare to similar products being offered?

How will you let others know about your product, and how will you develop its presentation to appropriate markets?

CARD 405 Week 3 Discussion 2,

Informational Interview

There are FIVE steps to the Informational Interview.

Step 1: Compile a list of individuals in your target career field whom you would like to interview. Try to identify people who are working at a company in which you are interested. This is a good opportunity to practice your networking skills. Let your classmates, friends, family members, and colleagues know that you need to complete an informational interview with someone in your intended career field. You’ll be amazed at how effective networking can be.

Step 2: Prepare a brief introduction of yourself and the purpose(s) of the informational interview. Prepare a list of open-ended questions that would be appropriate to ask during the informational interview. An Internet search using “informational interview” will provide you with many examples of questions you might want to use.

Step 3: Practice your interview with a classmate, friend, family member, or colleague and ask them to critique your performance. Identify ways to improve based on their feedback.

Step 4: Set up a day and time for the interview. Record the interviewee’s responses to your questions. Send a thank-you letter, note, or email to the interviewee within two business days of completing the interview.

Step 5: Complete the table below.

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touristguidebuzz · 8 years ago

Text

Cuba – As a Volunteer for an Authentic Expedience

Out of Town Blog Cuba – As a Volunteer for an Authentic Expedience

Cuba – As a Volunteer for an Authentic Expedience

In mid-January, I flew from Tampa to Havana on a trip that would introduce me to a country that has been off limits for me (and most Americans) for most of my life. I participated in a one-week service program in Cuba with Global Volunteers, a non-profit, NGO based in Minneapolis.

View on block from my casa particular in Miramar, (suburb of Havana)

Along with 19 other volunteers ages 30-78, I spent a week on various work projects that included painting a fence at our base (The Cuban Council of Churches), spending time with seniors at a senior care center and working with students on English in an evening program. Another team did crocheting with a women’s group for part of the day.

Every afternoon we had a few hours of free time before working with students practicing English for about two hours. Later we all met for dinner, with our excellent team leader, Stephanie, at various locations. The trip was a combination of helping our host community and a wonderful cultural learning experience for a group of Americans, most of whom, had never been to Cuba.

Living the Locals

We stayed in Miramar, a nice residential suburb of Havana near many of the city’s foreign embassies. All 20 volunteers stayed in guest houses within three or four blocks of each other. We were two blocks from the water and near our base at the Council where we met each morning around 9:00.

The joy of staying in a suburb is that you have the opportunity to observe people going to work and school and regularly interact with the locals. Put simply, it is a more authentic experience than staying in a hotel. You feel like a part of the community, particularly since you are there to help in some small way.

Visiting and meeting with seniors at a seniors center in Havana

We walked throughout the area every day and night. I never felt nervous nor did we see anything that looked questionable. The only danger I encountered was the uneven sidewalks which like many of the buildings are in disrepair. Also in the evenings many streets did not have lights so we walked with caution and used flashlights when necessary.

Getting Connected

There is very little internet on the island. Missing connectivity, we asked our hosts about options. They told us there was an “Internet Park” about a twenty minute walk from my casa. There, they said, we could purchase a card from a mini mart or store, but we were told there are long lines and forms to fill out along with passport information. The alternative was to walk to a certain small park and connect with a young gentlemen and his pals who our hosts said would sell us a card for 5 Kooks (approx $5.00 ) for one hour of internet. The card provides a password and username.

My three new Global Volunteer friends and I decided to visit the park. It was trashed with empty beer cans and bottles and many young people on their phones sitting on the ground. There was a group of men standing around that looked like possibly our connection.

Street Photography in Cuba

We approached the young men, and they immediately offered each of us an internet card. With our $5. purchase complete we took a photo together with the “sellers” and then enjoyed the internet for about 30 minutes. (We kept the card for another day’s use.) Mission accomplished. As we walked back to our work site I wondered, would I even consider walking up to a stranger in, let’s say, Central Park or Chicago and purchasing an “off the grid” card with the hope it worked? And then take a photo with them? Probably not.

Night out – Havana

Music, Art and Entertainment

If you choose to stay the weekend, you have the option of adding on the weekend package of people-to-people activities. Or you can make your own plans for the weekend. The Global Volunteers program includes a tour of the Ernest Hemingway House, art galleries, Old Havana and a morning lecture from two local

professionals who discuss history, education and some politics. All and all it’s a great value that includes meals and accommodations.

My favorite weekend activity was the excellent quality live music everywhere day or night. Street entertainers, restaurants and bars and coffee shops all have talented solo or group performers. Artwork is plentiful and there is a wide variety of architecture including colonial, Spanish, Art Deco and contemporary.

Entrepreneurial Spirit

My students on two evenings were a young couple in their early 20s. Allen is an independent contractor at a tour company and is eager to learn English so he can better communicate with visitors. His wife Daniella takes care of the home. She knew some English and is eager to help him. We review his tour prices, look at what’s included and add some language to make the tours more appealing. We go over phrases such as, “Welcome to Havana, my name is Allen and I would love to show you my country. What is your name?

Selling onions :potatoes in the neighborhood

After some competitive analysis, we determine that he is competing with the fancy old American cars that all the tourists seem to love. Their hourly rate is $50 per hour. We work on an appropriate response. “Yes, those old American cars are beautiful, however, instead of $50 per hour you might want to consider my van at only $15 per hour.” Allen masters three or four sentences that we work on intensely for two nights. They are sure to enhance his business opportunities.

It’s a pleasure to see a 23-year-old happily married, entrepreneur with such enthusiasm and eagerness to succeed. When we finished the second night, he looked at me and said “God Bless you and thank you.” I was beginning to see how individuals can make a small but significant impact in a short time and, more importantly, understand these very warm and welcoming people.

Street Vendors in Havana

In addition there are people who are operating and creating small businesses out of their homes or garages that are serving meals, coffee/beer and other small businesses like repair shops and such. Homes are renting out rooms to visitors for additional income. This is all new and Cubans seem very happy with new opportunities.

Yes, the streets, sidewalks and many buildings are in disrepair, run down and there is much need for improved infrastructure, painting, plumbing, electrical etc. Litter is an issue in some neighborhoods. For many, work is hard to find and salaries are low. Supplies of every kind are limited. Many of the local grocery store shelves are sparsely stocked.

Looking Ahead

The refreshing thing is you sense the change that is coming. In a lively conversation with one of our casa owners, she described it like this. “It started like the snowball on top of the mountain, it’s rolling down and getting bigger and bigger and you cannot stop it.”

Walk in our neighborhood – Miramar

Tourists from all over world have been visiting Havana for years and now there are many American visitors. In Havana we saw a cruise ship, red double-decker tour buses and souvenir shops. Colorful flora and fauna are everywhere and a walk along the Malecon — a walkway along the sea wall — is the perfect place to people watch.

The city of three million is bursting with activity and a colorful history that people want to experience. It’s old, it’s new, it’s Spanish, European, modern, young and fun!

I only saw a small part of Cuba on this trip. But I’m sure I’ll return again to visit Varadero, Santiago de Cuba, Trinidad and other places on this fascinating island.