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Can The Motion Be Transported From Mercury To The Earth Moon?
I- The Moon Daily Motion Distance
The moon moves per solar day a distance = 2.574 million km = The Earth motion distance per solar day - but we don't see this motion of the moon-
The idea is proved– the Earth and the moon revolve together around the sun and that necessitates the two planets to move equal distances per solar day.
The idea tells us 2 facts
First Fact – the moon moves per solar day a distance = 2.574 million km
Second Fact – we don't see this motion of the moon
The Contraction Effect With Rate 1.0725
There's a contraction effect with the rate 1.0725 in the solar system, I proved it in point no (7-4)
Shortly
The moon moves per solar day a distance 2.574 million km = the Earth motion distance per solar day- BUT- the rate (1.0725) has effect on the moon motion distance but has No effect on the Earth motion distance –
As a result – the moon distance 2.574 million km be decreased to 2.4 million km –
By that there's a difference =176000 km
Means
The Earth motion distance per solar day is (2.574 million km) and the moon motion distance per solar day is (2.4 million km) and by that there's a difference =176000 km between the two distances which will cause the moon to separate the Earth in their motions
Means- the moon has to move this 176000 km (on the same solar day) otherwise the moon will be separated from the Earth in their motions
How can that be possible? Let's answer in the next point
II- The Transported Motion From Mercury To The Moon
I discovered that–
The distance 176000 km is passed by the moon under effect of Mercury motion-
Means- the motion is transported from Mercury to Venus and from Venus to the moon and this transported motion pushed the moon to pass this required distance 176000 km.
Here I need to suppose that – the transported motion among the 3 planets is a motion different from the planet original motion- means
The planets move their motions normally– but – the transported motion is an addition one- this motion is Pluto transported motion and Mercury transported this motion to Venus and Venus transported it to the moon
Also I have discovered a perpendicularity in the inner planets (proved in point no.7-4)
(notice we see the moon displacement daily 88000 km in the Earth sky but we don't see the second part of the motion)
DATA
(1)
(90/2π) x 4.095 million km daily = 58.65 million km
(2)
58.65 days x 4.095 million km daily = 243 million km (error 1%)
(3)
243 days x 3.024 million km daily = 2 x 365.25 million km
(4)
4224 days x 176000 km = 2 x 365.25 million km
(5)
116.75 days x 2.082 million km daily = 243 million km
But (116.75/π) = (9010/243)
58.65 days = Mercury Rotation Period
243 days = Venus Rotation Period
116.75 days = Venus Day Period
365.25 days = Earth Orbital Period
9010 mkm = Saturn Orbital Circumference
DISCUSSION
Let's summarize the idea of the (three first data)
Each planet motion defines the next planet cycle period but in a distance form
Shortly
Mercury moves in ((90/2π)= 14.3 days) a distance = 58.65 million km but this distance used as Mercury rotation period (58.65 solar days)
And
Mercury moves during its rotation period (58.65 days) a distance = 243 million km (1%) which is used as (243 solar days = Venus rotation period)
And
Venus moves during its rotation period (243 days) a distance= 2 x 365.25 million km (0.6%) which is used as (365.25 solar days = the Earth orbital period)
The Earth orbital period is also the moon orbital period around the sun
That shows we have a transported motion among the three planets where the transportation depends on the planets cycles periods
Data no. (4)
4224 days x 176000 km = 2 x 365.25 million km
This data is the important one – because
The value (2 x 365.25 million km) is produced by Venus motion during its rotation period – means – this is the transported value from Venus to the moon – typically – as the motion transportation from Mercury to Venus
And
The distance 176000 km is the required distance for the moon motion- as we have discussed in the previous point-
Shortly- the transportation of motion is done for this distance (176000 km) basically
And
4224 hours = 176 solar days = Mercury day period – but
One hour of Mercury motion = 24 hours of any planet motion – for that – the period 4224 hours (for Mercury) is seen as (4224 solar days) for the moon
Data No. (5)
116.75 days x 2.082 million km daily = 243 million km But (116.75/π) = (9010/243)
2.082 million km daily = Mars velocity
116.75 days = Venus day period
The data tells the transported motion reach also to Mars – but – we should remember – the energy is reflected from Venus to Mars by that the transported motion among the three planets (Mercury, Venus and the moon) is done on one side but the transportation to Mars is done by reflection of energy – here we have 2 groups
Mercury, Venus and the moon one group where Mars is another group
III- The Moon Motion Direction Definition
The next question asks
Let's suppose Mercury motion causes the moon to move this additional distance 176000 km- there are still two questions (first question - is the motion in the same direction) (second question – why do we see the moon moves 88000 km only?)
Let's answer in details in following
(a)
We agreed that – the moon original motion (2.574 million km) is Not seen by us – but –it's proved fact – because the Earth moves (2.574 million km) and the moon has to move this same distance to save the complying motion with the Earth
Now - this distance 2.574 mkm is decreased by 176000 km and be (2.4 million km)
(b)
Mercury motion causes the moon to move this 176000 km – but – understandable that the motion is (in different direction) from the moon original motion – for that reason we enable to see the moon moves in the Earth sky – we can't see the original motion – that proves the motion of (176000 km) is done in different direction
Now let's – If the motions are done in different directions- how the distances can be added to one another?!
(c)
Also we don’t see the motion of this distance (176000 km) but only we see the half of it (88000 km)- why can't we see the whole distance??
Shortly
The moon modifies the motion direction during its motion and by that the moon can add the distances to one another- this fact is proved strongly because the moon orbital apogee radius is changed by this modification – I should prove later.
Means - the transported motion is in different direction but the moon modifies this direction by using an intelligent technique in its motion – this technique is explained in the next point – but – for the second question – (why don't we see the distance 176000 km but only 88000 km?) this question I can't answer – because – there are 2 options for solution –
First option – the second part (88000 km) may be passed with the original motion direction and by that we can't see it because we can't see the original motion
Second option- Mercury velocity = 2 Mars velocity – it may have some connection between the planets velocities – means – the two planets velocities are defined based on one another and be used together
And based on that the distance 176000 km be passed in the space by the moon motion for a distance =88000 km – now let's explain the moon intelligent technique
IV- The Moon Orbital Apogee Radius Definition
Why Is The Orbital Apogee Radius = 406000 Km?
The moon daily displacement =88000 km and during 29.53 days (the moon day period) the displacements total be = 2.598 million km = 2π x 413600 km
The data tells us the moon orbital apogee radius should be 413600 km and also it tells, because the moon daily displacement (88000 km) is so long, the moon should revolve around the Earth through this apogee orbit its radius (413600 km) only and can't revolve around the Earth through any more near orbit…
Not Facts
The moon orbital apogee radius =406000 km only and the moon revolves around the Earth through near orbits and can reach to perigee radius (363000 km).
How Can The Moon Do That?
The intelligent moon creates an angle (θ) between its motion direction and its orbit horizontal level by that the real displacement (L) through the orbit be less than (88000 km) because it be (L = 88000 km cos θ), as a result the total displacements be less than (2.598 million km) and that makes the moon orbital apogee radius to be decreased from 413600 km to 406000 km.
We should pay attention to the angle (θ), because this angle controls the moon motion features – where- with the angle (θ) increasing the real displacement (L) be shorter and the moon can revolve around the Earth through more near orbits – but –with the angle (θ) deceasing the real displacement (L) be longer and that pushes the moon far from the Earth to more far orbits.
The moon orbital motion depends on this angle (θ) it tells θ1 = θ0 +1.7
where (θ1) = today angle and (θ0) =yesterday angle
1.7 degrees be used as the moon daily motion degrees for the equation
Notice No.(1)
As a result for the moon using of the angle (θ), the moon orbital radiuses be defined based on Pythagorean rule – because – the moon uses the angle (θ) in its motion – by that – Each point the moon passes shows this fact – and the radiuses be defined based on one another by Pythagorean rule – let's prove that
(363000 km)2 + (86000 km)2 = (373000 km)2
(373000 km)2 + (86000 km)2 = (384000 km)2
(384000 km)2 + (86000 km)2 = (392000 km)2
(392000 km)2 + (86000 km)2 = (406000 km)2 (error 1%)
Where
363000 km = The Moon Orbital Perigee Radius
373000 km = The Total Solar Eclipse Radius
384000 km = The Moon Orbital Distance
406000 km = The Moon Orbital Perigee Radius
Based on that – we see the moon motion uses Pythagorean rule
Notice No.(2)
The using of the angle (θ) causes to modify the motion direction during the month – where we know the directions aren't changed by that the moon technique can modify the angle gradually till enable the distances to be added one another.
Notice No.(3)
149.6 million km cos (26.4 deg) =413.6 million km = 1000 x 413600 km
And 413600 km cos (26.4 deg) = 363000 km
149.6 million km = Earth Orbital Distance
1000 = The rate between Mercury motion and Venus motion
The data tells the orbital apogee radius 413600 km is defined based on the Earth orbital distance (149.6 million km)- but – the intelligent moon modifies its position to enable itself to revolve around the Earth through more near orbit
V- The Transported Motion Effect (Planet Diameter Definition)
The analysis proves there's a transported motion from Mercury to the moon- and this motion is so important for the moon to compensate the contracted distance from the moon orbital motion distance (176000 km)- by that- the moon motion depends in fact on Mercury motion-
Mercury motion transportation necessitates to depend on Venus and by that a system is created between the three first planets based on this transported motion which helps the moon to move the additional required distance
But
Can we have a description explain how this motion is transported clearly?
Imagine we have a canal of moving water– and – on some point a perpendicular rod pushes the water – that will create A WAVE in water because we have 2 motions perpendicular on one another – then - (the wave is transported through the water) - this wave creates the planet (matter)- means- The matter is consisted of 2 motions perpendicular on one another– by that–This wave creates the planet DIAMETER
The idea is simple but its effect is massive –
The matter is created by 2 motions perpendicular on one another- by that –the perpendicularity on Mercury (point) created Mercury and defined its Diameter -
This is the main story in this discussion because the transported motion moves through the planets - means – the transported motion for the distance (176000 km) is just a cover for the transported motion among the planets which defines each planet diameter.
We should notice that- because the planets motions use different rates of time- the transported motion transport also the motion rate of time
For example-Mercury rate of time (1=176) is transported to the moon motion because we need to add the moon velocity (29.8 km/s) and by that the total velocity is 205.8 km/s and this velocity creates the rate (1=205.8)
NOTICE
We review the 3 features for the moon, Saturn and Pluto
(I)
We know
The moon feature (T1=T2) which is (the moon rotation period = the moon orbital period =27.3 days)- this feature creates a proportionality between the moon diameter and its orbital circumference – means – it creates a proportionality between the moon diameter and the planet diameters total (406000 km)
The three planets diameters are defined based on this distance (406000 km) prove the transported motion (2593836 km) created the same one effect on the three planets – even if this effect is seen in different feature for each planet.
(II)
Saturn features is (V1=V2) where
Saturn (9.7 km/s) moves in its rotation period (10.7 h) a distance = Saturn Circumference (error 1.3%)–means- Saturn Rotational Velocity= Saturn Orbital Velocity = 9.7 km/s
Now
Saturn Circumference = 378675 km = 406000 km /1.0725
The rate (1.0725) has a general effect on the solar system I have proved before.
By that – Saturn Circumference is created based on the same distance =406000 km = the planets diameters total- that shows it's the same one link between the three planets
We note
J (3- (1/2π) = 406000 km (The Planets Diameter Total)
J (1- (1/2π) = 120536 km (Saturn Diameter) –
where
J = Jupiter diameter 142984 km
The data shows Saturn diameter is created by the same rule defines the planets diameters total.
(III)
Pluto feature is (D1=D2)- means – Two Distances Should Be Equal
What are these 2 distances? Let's review the other planets features
The moon rotation period = the moon orbital period (T1=T2) and
Saturn rotational velocity = Saturn orbital velocity (V 1=V2)
Let's conclude
Pluto motion distance in its rotation period (D1) should be = Pluto motion distance in its orbital period (D2)! It's illogical
Pluto moves in its rotation period a distance D1=2593836 km and
Pluto moves in its orbital period a distance D2=37100 million km
37100 million km = 2593836 km x 14178
If D1 = D2 that necessitates (14178 = 1)! How can that be possible?
By the rate of time –
If one second of the moon motion be = 14178 seconds of Pluto motion –
The moon orbital circumference 2593836km will be equal Pluto orbital circumference 37100 million km – so we need the rate of time (1=14178) let's try to find it in following
(IV)
The planets motions use different rates of time–I have proved that in point no.(10)
And
The definition of the rate of time is known –it means – each motion has its own clock- for example – one hour of Mercury motion = 24 hours of any planet motion – means – while Mercury clock moves one hour any other planet clock will move 24 hours –
Here we have a rate of time (1=14178) that means we need 2 clocks – one clock moves (one second) while the other clock moves (14178 seconds) – and this rate of time is used for periods but because of the reflection of the energy we see both as distances – for that – this rate is used between the moon orbit and Pluto orbit.
There are 2 methods to create the rate (1=14178) which are
(First Method)
The final rate of time between Mercury and Mars is (1=2840) means – each second of Mercury clock be = 2840 seconds of Mars clock
Now
Mars velocity = 5.1 Pluto velocity and the rate of time is produced as velocities rate – means – each one second of Mars = 5.1 seconds of Pluto – this is the basic rule to define the rate of time – by that (14178 = 2840 x 5.1) - means
(1 second of Mercury Clock be = 14178 seconds of Pluto Clock)
We have succeeded to create the rate of time (1=14178) but between Mercury and Pluto while we needed this rate between the moon and Pluto!
(We Can Consider Mercury Is A Partner In The Moon Motion)
(Second Method)
One second of Venus Motion = 48 seconds of Saturn motion
(because 10747 days Saturn orbital period = 48 x 224.7 days Venus orbital period)
Uranus orbital inclination (0.8) has effect on this relationship as following
(48/0.8) =60
Means –
One second of Venus Motion = 60 seconds of Saturn motion
And the energy is reflected from Venus to the moon and caused to reflect the players
Means –
One Second Of The Moon Motion = 60 Seconds Of Venus Motion
As a result
One Second Of The Moon Motion = 3600 Seconds Of Saturn Motion
And
14178 = 3600 x 3.93
Shortly
The rate tells (one second of the moon motion = 14178 seconds of Pluto motion) and in details the rate be
one second of the moon motion = 3600 seconds (one hour) of Saturn motion and
one second of Saturn motion = 3.93 seconds of Pluto motion – let's prove that
(i)
as we have seen the distance 2593836 km is seen as a distance for the moon and as a period 2593836 hours for Saturn- means – (one km of the moon = one hour of Saturn) but the moon daily displacement is 88000 km and its velocity is almost (1 km/s)
means – one km per hours for Saturn is equivalent to one km per second for the moon which necessitates to conclude the rate of time (1s of the moon =3600 s of Saturn)
(ii)
Pluto orbital distance 5906 km = 3.93 x 1503 million km
(Saturn orbital distance is 1433.5 million km has error 5%)
That shows the rate 3.93 works between Saturn and Pluto also
(V)
The three planets diameters are defined based on the distance (406000 km= the planets diameter total) – let's provide the data in following
366556 km = 2390 km (Pluto diameter) x 153.3
366556 km = 3475 km (The moon diameter) x (655.7/2π)
Where
153.3 hours = Pluto Rotation Period
655.7 hours = The Moon Rotation Period
366556 km = The Outer Planets Diameters Total
The data shows the moon and Pluto diameters depends on the 366556 km
And Saturn diameter depends directly on 406000 km based on the rate 1.0725 as have discussed before.
Thanks a lot – kind regards
Please read
Planet Diameter Equation Shows The Matter Origin (The Proves Discussions)
or
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
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