#mathisfun

[multimemes]

[fretbored34]

This is not incorrect 🤔

[wtfearth123]

Belphegor's prime is the palindromic prime number corresponding to (10³⁰ + 666 × 10¹⁴ + 1). The number itself contains superstitious elements: it has 666 at its heart, it's surrounded on either side by 13 zeroes and is 31 digits in length (13 reversed).

Belphegor’s prime is a very special number that has many interesting properties and connections to mathematics, numerology, and mythology. Belphegor’s prime is a palindromic prime, which means it is a prime number that reads the same backwards and forwards. A prime number is a positive integer that has exactly two factors: itself and one. For example, 2, 3, 5, 7, 11, … are prime numbers. Belphegor’s prime can be expressed in scientific notation as shown in the image below.

Belphegor’s prime is named after Belphegor, one of the Seven Princes of Hell, who is the demon of inventiveness. He is often depicted as a horned beast or a beautiful woman, and he tempts people with wealth and power. He is also associated with the deadly sin of sloth. It contains many superstitious elements that have given it its name. The most obvious one is the number 666, which is widely regarded as the Number of the Beast, a symbol of the Antichrist or the Devil in Christian tradition.

Belphegor’s prime number is surrounded by 13 zeros on each side, and the whole number has 31 digits, which is 13 reversed. Both 13 and 31 are considered unlucky numbers in some cultures. Moreover, this number can be written as shown in below image which emphasizes the unluckiness built in with this netherly prime by literally placing a 13 on each side of the devil’s number.

Belphegor’s prime is also related to some mathematical concepts and puzzles. For instance, it can be seen as a special case of a repunit prime, which is a prime number that consists of only one repeated digit (such as 11, 111, 11111, …). Belphegor’s prime is a repunit prime in base 10¹⁴+666

It is also connected to the Fermat primes, which are primes of the form (such as 3, 5, 17, 257, …).

Belphegor’s prime can be obtained by multiplying two Fermat primes:

2¹⁶+1

&

2³²+1

Furthermore, Belphegor’s prime can be used to construct a magic square of order 4 with a magic constant of 10¹⁵+333×10⁷+(1/2)

I hope this gives you some insight into the fascinating nature of Belphegor’s prime. 🙏

[sailing-the-cylindrical-sea]

Calculus Made Easy, by by Silvanus P. Thompson, 1910. Full text available online.

Love this book. I read it after already learning calculus, but I learned a lot about how to teach a complicated subject in an approachable way.

[trunkards]

Trunkards #607. Make peace with your limitations.

© 2023 Rick Hutchins

[internetforestwatcher]

“There are no secrets to success. It is the result of preparation, hard work, and learning from failure.”

― General Colin Powell

[friendtutor]

Grade 7 Maths lines and angles solved problems for more maths problema check the below link

[mathsatyourfingertips]

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[lionmageaz]

Watch "Fibonacci = Pythagoras: Help save a stunning discovery from oblivion!" on YouTube

This video demonstrates some mind blowing relationships between the Fibonacci series and the Pythagorean theorem. It ends with some beautiful fractal porn.

[anniejeugeune]

Fuck I'm Failing Math help me !!

[excellencet-shirt]

[sssmaths]

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[fretbored34]

All I got from this is:

Lego + foot = pain 😬

[sgt-cookie-2]

I'm no mathematician, but, wouldn't it be possible to make this task infinitely easier by dividing the countless numbers into various groups? The trick of it, time wise, would be to determine the minimum number of groups needed.

This does require us to make the assumption that, in this situation, we can communicate with all these people simultaniously, so as to organise and reorganise them as you like, asking them any question and what-not at your leisure.

So what's the gameplan here? Simple. We want as big of a group as possible to forgive you all at once in as few questions as possible. Then you go to the next biggest group that needs something more specialised before they forgive you, then the next biggest group with something even more specialised, until you're left with only a few stragglers that require something more specialised than could reasonably performed by even an AI.

For example, the first group you start off with would be "How many of you would forgive me right now?". There's going to be a non-zero chance that you've taken out a chunk of the people there. But where do you go from there and was that even the best opening question?

From there, maybe the next opening move is to divide the remaining groups into how long it would take for them to forgive you. Let's say for now, you split them between anything above a minute and anything below a minute. From there, you could divid them between anything above 5 minutes and everything 5 minutes and below. You go to the 5 minutes and below group. You divide them again and again and again in this manner until you get to the groups that will be willing to forgive you in only a second.

However, you've also set those groups up so that their "forgivenes timers" overlap. So, if three seconds pass, the "One Second Forgiveness Group" forgives you on the first second. The "Two Second Forgiveness Group" forgives you on the second second and the "Three Second Forgiveness Group" forgives you on the third second. In this way, you've organised every group so that every second another group forgives you. However, no matter how you arrange the groups, the "Two Second Forgiveness Group" never contains more members than less than half the "One Second Forgiveness Group", but never less than a quarter (I.e, if OSFG has 100 members, TSFG will never have more than 49 but will never have less than 25, but it can have any amount between those two, so the TSFG could have 36 members.). This applies to the "Three Second Forgiveness Group" and so on and so forth down the line.

Given a certain population size (X), and the number of seconds it took for them all to forgive you (Y), can you determine the minimum number of groups needed (Z) and, therefore, their likely population sizes (Q1, Q2, Q3, etc)?

[memeloverrrrr]

comments i got on math exams

?

incomplete

unfinished

F

[trunkards]

Trunkards #574. This web comic is provided for entertainment purposes only and should not be construed to imply the intrinsic superiority of one medium of artistic expression over another. No numbers were harmed in the making of this presentation.

© 2022 Rick Hutchins